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3 years ago

10

The main reason that cells carry out cellular respiration is to _______. A. Release energy B. Get glucose C. Breathe D. Eliminat

e wastes

1 answer:

UNO [17]3 years ago

4 0

A. Release energy

....................................

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HEY Plzzzzzzzzzzz HELP ILL GIVE BRAINLIEST ASAPPPPPPPPPPP

vladimir1956 [14]

1. Equal
2. Properties
3. Heat
4. Reverse

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3 years ago

Is the part of an experiment that is not being tested and is used for comparison

Vera_Pavlovna [14]

Answer:

Independent variable

Explanation:

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3 years ago

Read 2 more answers

The chemical formula for the ionic compound aluminum sulfite is Al2(SO3)3. Explain why there are 2 cations for every 3 anions in

svp [43]

Answer:

Explanation:

While trying to write the chemical formula for a compound (a neutral molecule), one must identify and exchange the charge of the cation with that of the anion to become the subscript of one other. For example

Aluminium oxide has Aluminium (Al) and oxygen (O); since Al has a charge of 3+ (the cation) and O has a charge of 2- (the anion), the compound would have it's charges as Al³⁺O²⁻ and when the charges are exchanged to there subscripts, it would form Al₂O₃; thus there would be two cations of aluminium for every three anions of oxygen in order to have a neutral molecule.

This same explanation can be given to Aluminium sulfite. Aluminium sulfite has Aluminium (Al) and sulfite (SO₃). Al has a charge of 3+ (cation) while sulfite has a charge of 2- (anion), with the compound having it's charges as Al³⁺(SO₃)²⁻ and when the charges are exchanged to there subscripts, it would form Al₂(SO₃)₃ and would thus have 2 cations of aluminium (Al³⁺) for every 3 anions of sulfite (SO₃³⁻) in order to have a neutral molecule.

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3 years ago

Q10.An aqueous solution contains 5.00x10-2 mol/L of Ca2+ and 7.00x10-3 mol/L of SO4

romanna [79]

Answer:

The precipitate will form.

Explanation:

Let's write the equilibrium expression for the solubility product of calcium sulfate:

$CaSO_4(s)$ ⇄ $Ca^{2+}(aq)+SO_4^{2-}(aq)$

The solubility product is defined as the product of the free ions raised to the power of their coefficients, in this case:

$K_{sp}=[Ca^{2+}][SO_4^{2-}]=10^{-4.5}$

Our idea is to find the solubility quotient, Q, and compare it to the K value. A precipitate will only form if Q > K. If Q < K, the precipitate won't form. In this case:

$Q_{sp}=[Ca^{2+}][SO_4^{2-}]=5.00\cdot10^{-2} M\cdot7.00\cdot10^{-3} M=3.5\cdot10^{-4}$

Now given the K value of:

$K_{sp}=10^{-4.5}=3.2\cdot10^{-5}$

Notice that:

$Q_{sp}>K_{sp}$

This means the precipitate will form, as we have an excess of free ions and the equilibrium will shift towards the formation of a precipitate to decrease the amount of free ions.

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4 years ago

The above structure exhibits three rings. Identify which of the rings are aromatic. Enter the numbers in ascending order separat

sertanlavr [38]

Answer:

The aromatic ringsare the number 1 and 2.

Identify which lone pairs are participating in resonance (in aromatic rings).

One lone pair on the sulfur atom.

Explanation:

For a compound to be aromatic it has to comply with Hückel's Rule, which says that the quantity of electrons in the pi orbitals, has to be a multiple of

4n + 2

for n = 0, 1, 2, 3.

5 0

3 years ago