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Goshia [24]
3 years ago
6

What is the mole fraction of cation in 1M of aluminium sulphate​

Chemistry
1 answer:
Svetllana [295]3 years ago
8 0

The mole fraction of cation (Al)=0.4

<h3>Further explanation</h3>

Given

1 M of Aluminium sulphate​

Required

The mole fraction of cation

Solution

Ionization of the Aluminum sulfate solution( assume 1 L solution ) :

mol Al₂(SO₄)₃ = M x V = 1 M x 1 L = 1 mol

Al₂(SO₄)₃⇒2Al³⁺ + 3SO₄²⁻

1 mol          2 mol   3 mol

From this equation, total mol in solution = 2+3 = 5 moles

Mol fraction Al(as a cation) :

= 2/5=0.4

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The grams  of the sugar in 125 g of the drink is calculated as below

%M/m) = mass of the solute (sugar)/  mass of the  solvent(drink) x100

let the mass  of the solute(sugar) be represented by y

convert % into fraction by dividing by 100 = 10.5/100

10.5/100 = y/125

by cross multiplication

100y =1312.5
divide both side by 100

y=13.125  grams


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