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3 years ago

HEY Plzzzzzzzzzzz HELP ILL GIVE BRAINLIEST ASAPPPPPPPPPPP

Chemistry

1 answer:

vladimir1956 [14]3 years ago

3 0

1. Equal
2. Properties
3. Heat
4. Reverse

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It's about coronovirus

sergij07 [2.7K]

Answer: what is it

Explanation:

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3 years ago

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Based on the following information, Cl2(g) + 2 e- → 2 Cl-(aq) E° = + 1.36 V Mg2+(aq) + 2 e- → 2 Mg(s) E° = -2.37 V which of the

Alex

Answer:

D) Mg(s)

Explanation:

We are given:

$E^o_{(Cl_2/Cl^-)}= 1.36V\\E^o_{(Mg^{2+}/Mg)}=-2.37V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, chlorine will undergo reduction reaction will get reduced. Magnesium will undergo oxidation reaction and will get oxidized.

<u>Reducing agents are the species which reduces others and oxidizes itself. Thus, Magnesium will be the strongest reducing agent.</u>

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4 years ago

You are given a bottle of NaOH of an unknown concentration. You are tasked with determining the concentration of this solution.

Salsk061 [2.6K]

Answer:

0.07975 M NaOH

Explanation:

First determine the molarity of your acid, KHP. Convert grams to moles using the MW given and then divide by the volume of water.

0.3175 g KHP • (1 mol KHP / 204.2 g KHP) = 0.001555 mol KHP

0.001555 mol KHP / 0.040 L = 0.03888 M KHP

The reaction between KHP and NaOH is one-to-one, so you can just use M1V1 = M2V2 to solve for M2 (the molarity of NaOH).

M1 = 0.03888 M KHP

V1 = 40 mL

M2 = ? M NaOH

V2 = 19.45 mL NaOH

(0.03888 M KHP)(40 mL) = M2(19.5 mL NaOH)

M2 = 0.07975 M NaOH

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3 years ago

What is produced during radioactive decay?

Rainbow [258]

D. Both particles and high energy radiation

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3 years ago

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Determine the specific heat of a 70 g sample of material that absorbed 96 J as it was heated from 293 K to 313 K

Damm [24]

This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:

<h3>Calorimetry:</h3>

In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:

$Q=mC(T_f-T_i)$

Thus, one can get the specific heat by solving for C in the previous equation:

$C=\frac{Q}{m(T_f-T_i)}$

Hence, we can plug in the given data to obtain:

$C=\frac{96J}{70g(313K-293K)}\\ \\C=0.0686\frac{J}{g*K}$

Learn more about calorimetry: brainly.com/question/1407669

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2 years ago