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3 years ago

-7x + y = -19 –2x+3y=-19

Mathematics

1 answer:

ZanzabumX [31]3 years ago

6 0

Answer:x=3,y=-5

Step-by-step explanation:

-7x+y=-19...(1)

-2x+3y=-19...(2)

Subject of formula from (1)

Y=-19+7x....(3)

Substitute (3) into (2)

-2x+3(-19+7x)=-19

-2x-57+21x=-19

Collect like terms

-2x+21x=-19+57

19x=38

X=2

Substitute x=2 to equation (3)

Y=-19+7(2)

Y=-19+14

Y=-5

X=2 and y=-5

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2 years ago

Is the given value a solution to the equation? 4(n) - 3 = -2(n) + 9 n=2

nlexa [21]

Answer:

Yes!

The solution to the equation is n = 2

Step-by-step explanation:

Given the equation

$4\left(n\right)-3=-2\left(n\right)+9$

remove the parentheses

$4n-3=-2n+9$

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$4n-3+3=-2n+9+3$

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Simplify

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Hence,

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3 years ago

Standred from and word from

Orlov [11]

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2 years ago

Read 2 more answers

How to show these 2 problems are inverses

nataly862011 [7]

$\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x$

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other

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2 years ago