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1 year ago

6.

Mathematics

1 answer:

vova2212 [387]1 year ago

4 0

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A garden is going to be built in the city park in the shape of a parallelogram with a rectangular walkway through it. The garden

Natali [406]

Answer:

78*78+30*30+20*20+72

7456

Step-by-step explanation:

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2 years ago

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Help please!

Mamont248 [21]

Answer: see proof below

<u>Step-by-step explanation:</u>

Use the Sum & Difference Identity: cos (A + B) = cos A · cos B - sin A · sin B

Recall the following from Unit Circle: cos (π/2) = 0, sin (π/2) = 1

cos (π) = -1, sin (π) = 0

Use the Quotient Identity: $\tan A=\dfrac{\sin A}{\cos A}$

<u>Proof LHS → RHS:</u>

$\text{LHS:}\qquad \qquad \dfrac{\cos \bigg(\dfrac{\pi}{2}+x\bigg)}{\cos \bigg(\pi +x\bigg)}$

$\text{Sum Difference:}\qquad \dfrac{\cos \dfrac{\pi}{2}\cdot \cos x-\sin \dfrac{\pi}{2}\cdot \sin x}{\cos \pi \cdot \cos x-\sin \pi \cdot \sin x}$

$\text{Unit Circle:}\qquad \qquad \dfrac{0\cdot \cos x-1\cdot \sin x}{-1\cdot \cos x-0\cdot \sin x}$

$=\dfrac{-\sin x}{-\cos x}$

Quotient: tan x

LHS = RHS $\checkmark$

7 0

3 years ago

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What is the answer. please help

zubka84 [21]

Answer:

Exact Form:−2/3

Decimal Form:−0.666…

Step-by-step explanation:

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1 year ago

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Pie

Answer:

Step-by-step explanation:

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2 years ago

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Write an equation in slope intercept form for the line that passes through (-1, -2) and (3, 4)

LenaWriter [7]

Answer:

The slope-intercept form of the line equation is:

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

m is the slope

b is the y-intercept

Given the points

(-1, -2)

(3, 4)

Determining the slope between (-1, -2) and (3, 4)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)$

$m=\frac{4-\left(-2\right)}{3-\left(-1\right)}$

$m=\frac{3}{2}$

Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

$4=\frac{3}{2}\left(3\right)+b$

switch sides

$\frac{3}{2}\left(3\right)+b=4$

$\frac{9}{2}+b=4$

subtract 9/2 from both sides

$\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}$

$b=-\frac{1}{2}$

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

$y = mx+b$

$y=\:\frac{3}{2}x\:+\:\left(-\frac{1}{2}\right)$

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

Therefore, the slope-intercept form of the line equation is:

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

8 0

2 years ago