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Rina8888 [55]
3 years ago
7

How would I do part A. I showed my work but I'm slightly off

Mathematics
1 answer:
ahrayia [7]3 years ago
5 0

\bf \stackrel{\textit{perimeter of the rectangle}}{P_{rect}=2x+y}~\hfill \stackrel{\textit{area of the rectangle}}{A_{rect}=xy}
\\\\\\
\stackrel{\textit{perimeter of the semi-circle, with }r=\frac{y}{2}}{P_{semic}=\cfrac{\pi y}{2}}~\hfill \stackrel{\textit{area of the semi-circle with }r=\frac{y}{2}}{A_{semic}=\cfrac{\pi y^2}{8}}
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \stackrel{\textit{perimeter of the enclosure}}{60=2x+y+\cfrac{\pi y}{2}}\implies \stackrel{\textit{multiplying by 2}}{120=4x+2y+\pi y}
\\\\\\
120-2y-\pi y=4x\implies \cfrac{120-2y-\pi y}{4}=x
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \stackrel{\textit{area of the enclosure}}{A=xy+\cfrac{\pi y^2}{8}}\implies A=\left( \cfrac{120-2y-\pi y}{4} \right)y+\cfrac{\pi y^2}{8}
\\\\\\
A=\cfrac{120y-2y^2-\pi y^2}{4}+\cfrac{\pi y^2}{8}\implies A=\cfrac{240y-4y^2-2\pi y^2+\pi y^2}{8}
\\\\\\
A=\cfrac{240y-4y^2-\pi y^2}{8}\implies A=\cfrac{240y}{8}-\cfrac{4y^2}{8}-\cfrac{\pi y^2}{8}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill A=30y-\cfrac{1}{2}y^2-\cfrac{1}{8}\pi y^2~\hfill

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I need help on both of the question
garri49 [273]

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6 0
2 years ago
Oose the situation which would best be modeled by an exponential decay function.
alexandr1967 [171]

Answer:

The following would be best modeled by an exponential decay function

A.) An island is being eroded away and loses 10% of its beachfront every year.

D.) A machine depreciates (loses value) by $1000 in its first year, by $2000 in its second, $3000 in its third, etc.

Step-by-step explanation:

The following would be best modeled by an exponential decay function

A.) An island is being eroded away and loses 10% of its beachfront every year.

D.) A machine depreciates (loses value) by $1000 in its first year, by $2000 in its second, $3000 in its third, etc.

6 0
3 years ago
Suppose you wish to borrow $600 for two weeks and the amount of interest you must pay is $25 per $100 borrowed. What is the APR
Yuliya22 [10]

Answer:

The APR at which the money is borrowed, is approximately 651.79%

Step-by-step explanation:

The amount which one wishes to borrow for two weeks, P = $600

The amount of interest that one must pay back = $25 per $100 borrowed

Therefore;

The total interest on the $600 loan (borrowed) for two weeks = 25/100× $600 = $150

The number of days for which the amount was borrowed = 2 weeks = 14 days

The Annual Percentage Rate, APR is given as follows;

APR = \left (\dfrac{\left (\dfrac{Interest \ Paid \ for \ the  \ Loan \ duration}{The \ amount \ borrowed} \right )}{The \ number \ of \ days \ the \ amount \ was  \ borrowed } \right ) \times 365 \times 100

Therefore, we get

APR = \left (\dfrac{\left (\dfrac{150}{600} \right )}{14 } \right ) \times 365 \times 100  \approx 651.79 \%

The annual rate at which the money is borrowed, APR ≈ 651.79%.

8 0
3 years ago
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