A triangle with an area of 23 cm² is dilated by a factor of 6.

1 answer:

8 0

For this item, I will assume that we are required to give the area of the dilated triangle. By dilated we mean to say that the dimensions of the second triangle is 6 times that of the first. We square 6 and them multiply this to the area of the original triangle to get the area of the second. That is,
area of second triangle = (2/3 cm²)(6²) = 24 cm²
Thus, the area of the new triangle is equal to 24 cm².

You might be interested in

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

3 years ago

Please helppppp me What’s the answer?

taurus [48]

Answer:

She shaded above the line when she should have shaded below the line.

Step-by-step explanation:

hope this helps and is right. p.s. i really need brainliest :)

if this is wrong then I am incredibly sorry!

5 0

2 years ago

Problems