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Effectus [21]
3 years ago
7

-25 POINTS- Which of the following terms best describes the figure below?

Mathematics
2 answers:
suter [353]3 years ago
6 0

Answer:

figure???????????????????????????????????????

Step-by-step explanation:


Mashutka [201]3 years ago
4 0
What figure you have not put up the figure

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Solve for x: 8x + 10 - 5x = 15.
MrRa [10]
<span>8x + 10 - 5x = 15
3x + 10 = 15
3x = 5
  x = 5/3

hope it helps</span>
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3 years ago
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7.5 cm=__ m <br><br> A.0.0075<br> B.0.075<br> C.0.75<br> D.750
spayn [35]

Your answer is B. 0.075 m

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3 years ago
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A secret formula for eternal youth, f (x), was discovered by Dr. Quick, who has been working in our biotech company. However, Dr
charle [14.2K]

Answer:9

Step-by-step explanation:3x3= 9

(X3x3x3)

=9p

8 0
3 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
Sierra left $4.50 as a tip for a waiter. This was 18% of the bill before the tip. How much was her total bill before the tip? En
IrinaVladis [17]

Answer: $20.5

Step-by-step explanation:

Let x  denotes the amount for total bill.

We are given that ,  Sierra left $4.50 as a tip for a waiter.

This was 18% of the bill before the tip.

We can write 18% = 0.18. [To convert percent into decimal we divide it by 100.]

Then, the tip amount = 0.18 x Total bill

\Rightarrow\ 4.5=0.18x\\\\\Rightarrow\ x=\dfrac{4.5}{0.18}=25

So, the total bill amount = $25

Hence, her total bill before the tip= Total bill amount - Tip amount

= $25- $4.50=$20.5

Thus ,her total bill before the tip= $20.5

6 0
3 years ago
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