1 year ago

Find the answer a b c d

Mathematics

1 answer:

Airida [17]1 year ago

8 0

Answer: a

Step-by-step explanation:

$\left(\frac{f}{g} \right)(x)=\frac{f(x)}{g(x)}=\frac{\sqrt{x^{2}-1}}{\sqrt{x-1}}}=\sqrt{\frac{x^{2}-1}{x-1}}=\sqrt{\frac{(x-1)(x+1)}{x-1}}=\boxed{\sqrt{x+1}}$

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