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maw [93]
3 years ago
9

Which equation is the inverse of y = x2 + 16? 0 y=x²-16 y=i -16 y=+-16 y = x2 - 4

Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

y = ±√(x-16)

Step-by-step explanation:

To find the inverse of an equation, swap the x- and y-variables:

y = x² + 16

x = y² + 16

Then, solve for the y-variable:

x = y² + 16

y² = x - 16

y = ±√(x-16)

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Use format y = mx + b

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section of a pipe's length and weight are in proportion. If 2.5 m of pipe weighs 10 kg, then A) 5 m of pipe weighs 30 kg. B) 5 m
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We will proceed to resolve each case to determine the solution.

we know that

2.5 m of pipe weighs 10 kg

so

by proportion

<u>Find the weighs of each case</u>

<u>case A)</u> 5 m of pipe weighs 30 kg

\frac{10}{2.5}\frac{kg}{m}=\frac{x}{5}\frac{kg}{m}\\ \\2.5*x=5*10\\ \\x=50/2.5\\x=20\ kg

20\ kg\neq30\ kg

therefore

The statement case A) is False

<u>case B)</u> 5 m of pipe weighs 40 kg

\frac{10}{2.5}\frac{kg}{m}=\frac{x}{5}\frac{kg}{m}\\ \\2.5*x=5*10\\ \\x=50/2.5\\x=20\ kg

20\ kg\neq40\ kg

therefore

The statement case B) is False

<u>case C)</u> 10 m of pipe weighs 40 kg

\frac{10}{2.5}\frac{kg}{m}=\frac{x}{10}\frac{kg}{m}\\ \\2.5*x=10*10\\ \\x=100/2.5\\x=40\ kg

40\ kg=40\ kg

therefore

The statement case C) is True

<u>case D)</u> 10 m of pipe weighs 80 kg

\frac{10}{2.5}\frac{kg}{m}=\frac{x}{10}\frac{kg}{m}\\ \\2.5*x=10*10\\ \\x=100/2.5\\x=40\ kg

40\ kg\neq80\ kg

therefore

The statement case D) is False

therefore

<u>the answer is</u>

10 m of pipe weighs 40 kg


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