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saveliy_v [14]
3 years ago
14

Math Help!!! How many x-intercepts does the graph of the function have?

Mathematics
2 answers:
dalvyx [7]3 years ago
6 0
It can have however many x intercepts it wants, 

<span>BUT, to be a function it must pass the vertical line test. </span>
<span>this means you have to look at the graph and see if a vertical line drawn anywhere hits the graph more than once. </span>
<span>if it hits it more than once, it is NOT a function. 
</span>
An example is a polynomial function to the infinite degree. That is 
f(x) = lim (n --> infinity) [ x^n] 
but only 1 y intercept (vertical line test remember)


Contact [7]3 years ago
5 0
If you are given a parabolic function you can algebraically determine the type of zeros of the function with the discriminant, which is b^2-4ac.

The discriminant is derived from the quadratic formula, x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}.
The discriminant is what's inside the square root (the radicand).

If the radicand is negative, there will be 2 imaginary numbers (there are two because of the plus or minus before the square root)
If the radicand is positive, there will be 2 real numbers.
If the radicand is zero, the answer will be 0.

Therefore,
If discriminant is negative, there are 2 complex zeros.
If discriminant is positive, there are 2 real zeros.
If discriminant is zero, there is one real zero.

A zero is basically the x-intercept.

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z^{\circ}=180^{\circ}-90^{\circ}-52^{\circ} \\z^{\circ}=90^{\circ}-52^{\circ} \\z^{\circ}=38^{\circ}

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I couldn't see the picture it is black

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100

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