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expeople1 [14]
3 years ago
5

Need help with math

Mathematics
1 answer:
vampirchik [111]3 years ago
4 0
Idk what u want to know
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Complete the equation of the line whose y-intercept is (0, -1) and slope is 4.<br> (Khan academy)
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Answer:

y = 4x - 1

Step-by-step explanation:

y = mx + b

Here m is slope and b is y-intercept

m = 4;  b = -1  

y = 4x - 1

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the answer is 35.0° pls thank :)

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Find an equation of the plane through the point (1, -5, 3) and perpendicular to the vector (2, -3, -3).
AnnyKZ [126]
<span>2x - 3y - 3z = 8
   We've been given the normal vector to the plane <2, -3, -3> and a point within the plane (1, -5, 3). In general if you've been given both the normal vector <a,b,c> and a point (e,f,g) within the plane, the expression for the plane will be: ax + by + cz = d
 and you can compute d by:
 d = ae + bf + cg
   So let's calculate d:
 d = ae + bf + cg
 d = 2*1 + -3*-5 + -3*3
 d = 2 + 15 + -9
 d = 8
   And the equation for the plane is 2x - 3y - 3z = 8</span>
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3 years ago
Tan(43)=1347/x <br> Can someone help please
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