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3 years ago

Solution X has a pH of 9.4, and solution Y has a pH of 7.4.

Chemistry

2 answers:

vodomira [7]3 years ago

8 0

Answer:

a. [H30+] = 4 * 10^-10 M

b. [H3O+]= 4 * 10^-8 M

Explanation:

Step 1: Data given

pH of solution X = 9.4

pH of solution Y = 7.4

Step 2: Calculate [H3O+] of solution X

pH = -log [H+]

[H+] = [H30+]

pH = -log[H3O+]

9.4 = -log[H3O+]

10^-9.4 = 3.98*10*-10

[H30+] = 4 * 10^-10 M

To control we can calculate pH

-log[4 * 10^-10] = 9.4

Step 3: Calculate [H3O+] of solution Y

pH = -log [H+]

[H+] = [H30+]

pH = -log[H3O+]

7.4 = -log[H3O+]

10^-7.4 = 4*10*-8

[H30+] = 4 * 10^-8 M

To control we can calculate pH

-log[4 * 10^-8] = 74

a. [H30+] = 4 * 10^-10 M

b. [H3O+]= 4 * 10^-8 M

Whitepunk [10]3 years ago

4 0

Answer:

see below

Explanation:

[H₃O⁺] = 10^-pH

a) Soln X with pH = 4.9 => [H₃O⁺] = 10⁻⁴°⁹ = 2.51 x 10⁻⁵M

b) Soln Y with pH = 7.4 => [H₃O⁺] = 10⁻⁷°⁴ = 3.98 x 10⁻⁸M

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