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worty [1.4K]
3 years ago
13

6. What category of elements is found between the metals and nonmetals

Chemistry
1 answer:
iren [92.7K]3 years ago
3 0

Answer:

B. metalloids

Explanation:

The metalloids are found between metals and non-metals on the periodic table.

Metalloids have properties between those of metals and non-metals. Under certain prevalent conditions, they exhibit a set of properties.

  • Synthetic substances are those artificially made, they are not found on the periodic table.
  • Noble gases are found in the last group on the periodic table.
  • Radioactive substances are found in the lanthanide and actinide series.
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How dose soil texture determine soil fertility? Which of the anserws are correct PLZZZ HELPPP MEEE
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Answer is A

Explanation:

Important physical properties that affect fertility include soil structure and texture. Structure is the amount of aggregation and pores in soil and texture is the proportion of clay and sand particles in soil. Both affect soil fertility by affecting water movement through soil, root penetration and water logging.

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Ferrous sulfate (FeSO4) was used in the
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Ferrous sulfate (FeSO4) is obtained by the reaction of aqueous ferric sulfate with gaseous sulfur dioxide and water according to the equation below:

Aqueous ferric sulfate = Fe_2(SO_4)_3_{(aq)}

Gaseous sulfur dioxide = SO_2_{(g)}

Water = H_2O_{(l)}

Aqueous sulfuric acid =  H_2SO_4_{ (aq)}

Aqueous ferrous sulfate =  FeSO_4_{ (aq)}

Thus, the balance equation becomes:

Fe_2(SO_4)_3_{(aq)} +  SO_2_{(g)} + 2H_2O_{(l)} ---> 2 H_2SO_4_{ (aq)} + 2 FeSO_4_{ (aq)}

More on ferrous sulfate can be found here:  brainly.com/question/10834028

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4 years ago
Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,
8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

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3 years ago
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