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Flura [38]
3 years ago
6

1.) -24 divided by 1/6 a. 4 b. 144 c. -4 d. -144 2.)

Mathematics
2 answers:
Dmitry [639]3 years ago
5 0
D is the answer if not reply back

almond37 [142]3 years ago
4 0
C negative 4 :) Hope that helps!!
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Quadrilateral QRST is a square. If the measure of RS is 12x + 5 and QT is 8x + 15. find the value of QR ​
valentina_108 [34]

Answer:

35

Step-by-step explanation:

I got you the answer is 35.

7 0
2 years ago
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Heya! ツ
fiasKO [112]

Answer:

See Below.

Step-by-step explanation:

In the given figure, O is the center of the circle. Two equal chords AB and CD intersect each other at E.

We want to prove that I) AE = CE and II) BE = DE

First, we will construct two triangles by constructing segments AD and CB. This is shown in Figure 1.

Recall that congruent chords have congruent arcs. Since chords AB ≅ CD, their respective arcs are also congruent:

\stackrel{\frown}{AB }\, \cong\, \stackrel{\frown}{CD}

Arc AB is the sum of Arcs AD and DB:

\stackrel{\frown}{AB}=\stackrel{\frown}{AD}+\stackrel{\frown}{DB}

Likewise, Arc CD is the sum of Arcs CB and DB. So:

\stackrel{\frown}{CD}=\stackrel{\frown}{CB}+\stackrel{\frown}{DB}

Since Arc AB ≅ Arc CD:

\stackrel{\frown}{AD}+\stackrel{\frown}{DB}=\stackrel{\frown}{CB}+\stackrel{\frown}{DB}

Solve:

\stackrel{\frown}{AD}\, \cong\,\stackrel{\frown}{CB}

The converse tells us that congruent arcs have congruent chords. Thus:

AD\cong CB

Note that both ∠ADC and ∠CBA intercept the same arc Arc AC. Therefore:

\angle ADC\cong \angle CBA

Additionally:

\angle AED\cong \angle CEB

Since they are vertical angles.

Thus:

\Delta AED\cong \Delta CEB

By AAS.

Then by CPCTC:

AE\cong CE\text{ and } BE\cong DE

5 0
2 years ago
Read 2 more answers
What is the simplified form of -24m^5 n^4/ 8m^-7 n^-2
solong [7]

Answer:

  -3·m^12·n^6

Step-by-step explanation:

We assume you intend ...

  (-24·m^5·n^4)/(8·m^-7·n^-2)

  = (-24/8)·m^(5-(-7))·n^(4-(-2))

  = -3·m^12·n^6

_____

If you really intend what you have written, then it simplifies to ...

  (-24·m^5·n^4/8)·m^-7·n^-2 . . . . . note that all factors involving m and n are in the numerator

  = (-24/8)·m^(5-7)·n^(4-2) = -3n^2/m^2

8 0
2 years ago
Frankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft. what will be
ira [324]

The length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.

<h3>What is the Pythagoras theorem?</h3>

The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.

We have:

Frankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft.

From the Pythagoras theorem:

Perpendicular(P) = 32 ft

Base(B) = 20 ft

H = √(32²+20²)

H = √1424

H = 37.7 ft

Thus, the length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.

Learn more about Pythagoras' theorem here:

brainly.com/question/21511305

#SPJ1

5 0
1 year ago
You are buying lawn seed for the the football field a 10 pound bag of lawn seed covers 2000 square feet.
Masja [62]

A football field is 120 yards long (100 yards playing field plus 2 end zones 10 yards each) by 53 1/3 yards wide.

1 yard = 3 feet.

120 yards x 3 feet per yard = 360 feet

53 1/3 yards x 3 = 160 feet.

The area of the football fields is 360 x 160 = 57,600 square feet.

1 bag covers 2000 square feet:

57,600 / 2,000 = 28.8 bags, round up to 29 bags are needed.

1 bag cost $27.79.

29 bags x $27.79 = $805.91 total cost.

7 0
3 years ago
Read 2 more answers
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