Answer:
35
Step-by-step explanation:
I got you the answer is 35.
Answer:
See Below.
Step-by-step explanation:
In the given figure, O is the center of the circle. Two equal chords AB and CD intersect each other at E.
We want to prove that I) AE = CE and II) BE = DE
First, we will construct two triangles by constructing segments AD and CB. This is shown in Figure 1.
Recall that congruent chords have congruent arcs. Since chords AB ≅ CD, their respective arcs are also congruent:

Arc AB is the sum of Arcs AD and DB:

Likewise, Arc CD is the sum of Arcs CB and DB. So:

Since Arc AB ≅ Arc CD:

Solve:

The converse tells us that congruent arcs have congruent chords. Thus:

Note that both ∠ADC and ∠CBA intercept the same arc Arc AC. Therefore:

Additionally:

Since they are vertical angles.
Thus:

By AAS.
Then by CPCTC:

Answer:
-3·m^12·n^6
Step-by-step explanation:
We assume you intend ...
(-24·m^5·n^4)/(8·m^-7·n^-2)
= (-24/8)·m^(5-(-7))·n^(4-(-2))
= -3·m^12·n^6
_____
If you really intend what you have written, then it simplifies to ...
(-24·m^5·n^4/8)·m^-7·n^-2 . . . . . note that all factors involving m and n are in the numerator
= (-24/8)·m^(5-7)·n^(4-2) = -3n^2/m^2
The length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.
<h3>What is the Pythagoras theorem?</h3>
The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.
We have:
Frankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft.
From the Pythagoras theorem:
Perpendicular(P) = 32 ft
Base(B) = 20 ft
H = √(32²+20²)
H = √1424
H = 37.7 ft
Thus, the length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.
Learn more about Pythagoras' theorem here:
brainly.com/question/21511305
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A football field is 120 yards long (100 yards playing field plus 2 end zones 10 yards each) by 53 1/3 yards wide.
1 yard = 3 feet.
120 yards x 3 feet per yard = 360 feet
53 1/3 yards x 3 = 160 feet.
The area of the football fields is 360 x 160 = 57,600 square feet.
1 bag covers 2000 square feet:
57,600 / 2,000 = 28.8 bags, round up to 29 bags are needed.
1 bag cost $27.79.
29 bags x $27.79 = $805.91 total cost.