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AURORKA [14]
3 years ago
12

Using V =iwh what is an expression for the volume of the following prism​

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Answer:

we know that

The volume of the prism is equal to

V=L*W*H

where

L is the length side of the base of the prism

W is the width side of the base of the prism

H is the height of the prism

In this problem we have

L=\frac{d-2}{3d-9}=\frac{d-2}{3(d-3)}

W=\frac{4}{d-4}

H=\frac{2d-6}{2d-4}=\frac{2(d-3)}{2(d-2)}=\frac{(d-3)}{(d-2)}

Substitute the values in the formula

V=\frac{d-2}{3(d-3)}*\frac{4}{d-4}*\frac{(d-3)}{(d-2)}=\frac{4}{3(d-4)}=\frac{4}{3d-12}

therefore

the answer is the option

4/3d-12

Step-by-step explanation:

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To rent a certain meeting room a college charges a reservation fee of $33 and an additional fee of $9.80 per hour the club wants
sammy [17]

Answer:

They must rent for less than 7 hours

Step-by-step explanation:

The charge for the room is the fee plus the hourly rate times the hour

f = 33+9.80t

This must be less than 101.60

101.60> 33+9.80t

Subtract 33 from each side

101.60-33> 33-33+9.80t

68.6> 9.80t

Divide each side by 9.8

68.8/9.8 > t

7>t

They must rent for less than 7 hours

7 0
2 years ago
A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

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The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
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Answer:

x = -3

Step-by-step explanation:

36(x + 4) = 36

Divide both sides by 36

x + 4 = 1

Subtraact 4 from both sides

x = -3

8 0
3 years ago
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Answer:

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Answer:

10

Step-by-step explanation:

She already has 75 points. 140-75 is 65. 65/6.5 is 10.

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