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hjlf
3 years ago
6

An adventurous dog strays from home, runs three blocks east, two blocks north, one block east, one block north, and two blocks w

est. Assuming that each block is about 100 m, how far from home and in what direction is the dog? Use a graphical method.

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0
<h2>Answer:</h2>

<u>Distance = 360.55 m</u>

<u>Direction = North-East</u>

<h2>Step-by-step explanation:</h2>

In the question,

The adventurous dog starts from O, say.

He moves 3 blocks East = 300 m

then,

2 blocks North = 200 m

1 block East = 100 m

1 block North = 100 m

2 blocks West = 200 m

So,

Distance of the Dog's <u>final position</u> from the <u>initial position</u><u>.</u>

OE is given by,

In triangle OLE, using Pythagoras theorem,

OE^{2}=OL^{2}+LE^{2}\\OE^{2}=(200)^{2}+(300)^{2}\\OE^{2}=40000+90000\\OE=360.55\,m

<em><u>Therefore, the distance of Dog from the Home is 360.55 m and the direction of Dog from Home is North-East.</u></em>

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