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3 years ago

What is the range of the function g(x) = |x – 12| – 2?

2 answers:

3 0

Your function is |x-h|+k where (h,k) is the vertex and the range will be greater than or equal to the y value of the vertex or k. So the range is greater than or equal to -2. This means the none of the answer choices are correct since none of them give the option of greater than or equal to. Seems to be an error though as both the top two answers and the bottom two are exactly the same.

katrin [286]3 years ago

3 0

The correct answer would be B in this case, he was just not able to put down a greater than or equal to sign. B.-y l y≥ -2

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Two dice are rolled. Define the events as follows: A : sum of 7, B : doubles, C : sum of 8

love history [14]

Answer: for a sum of 7 would either be 6 and 1, 5 and 2 or 4 and 3. you can roll a double 1,2,3,4,5,6. the sum of 8 would be 2 and 6, 3 and 5 and a double 4,

Step-by-step explanation:

well the there are six sides on a die so 6 x 2 is 12 so the max sum you can get is 12. So you take 7 and you start adding up to 7, same thing for sum of 8. since there is 6 sides and a pair of dices you will roll six doubles

5 0

3 years ago

1.56 times 48 equals

Crank

Answer:

It equals 74.88

Step-by-step explanation:

U jus multiply them

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3 years ago

Read 2 more answers

A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l

Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

$x+0.25x=20,000$

$1.25x=20,000$

$\frac{1.25x}{1.25}=\frac{20,000}{1.25}$

$x=16,000$

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

$x-0.20x=20,000$

$0.80x=20,000$

$\frac{0.80x}{0.80}=\frac{20,000}{0.80}$

$x=25,000$

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be $16,000+25,000=41,000$

The total sale price of both cars $20,000+20,000=40,000$ .

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

4 0

3 years ago

How many different 4 digit even numbers can be written using 0,5,6,3,8,7?<br><br> help asap please!!

fiasKO [112]

Step-by-step explanation:

I guess that means the digits can not be repeated in such a number.

let's start with how many numbers in general can be created :

we have 6 basic digits, and we are pulling 4 of them for a number.

if the sequence of the pulled digits would not matter, it would be combinations C (6, 4).

but we are creating different numbers, so the sequence of the digits does matter. so, it is permutations P (6, 4).

P(6, 4) = 6!/(6-4)! = 6!/2! = 6×5×4×3 = 360

so. bauxite, we can create 360 different 4 digit numbers out of these 6 digits.

but not all of them are wanted.

for example, I assume we don't want the numbers that start with a 0, because they would normally count as 3-digit numbers.

if that assumption is correct, we need to find how many would start with a 0, and subtract those from the total number.

since we are handling all 6 digits in the same way, an equal number must start with 0, with 5, with 6, with 3, with 8 and with 7.

so, 1/6 of the total number start with 0 : 360×1/6 = 60.

that means the total number of 4-digit numbers out of these 6 digits that do not start with 0 is 360-60 = 300.

but we are still not finished : we only want even numbers. that means they end with 0, 6 or 8.

in the same way we considered the first position, we consider also the last position. we have an equal amount of numbers that end with the different digits.

and so, we have 1/6 of 300 for each ending digit.

we want the specified 3 digits as end digits, so we get

3×1/6 of the 300 = 1/2 × 300 = 150

so, we can write 150 different 4-digit even numbers out of these 6 digits.

3 0

2 years ago

Need answer ASAP will give brainliest check out the picture

valentinak56 [21]

Answer:

i think... x=6

Step-by-step explanation:

3x+9=x+21

3x−x=12

2x=12

x=6

8 0

2 years ago