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kifflom [539]
3 years ago
15

What is 2+2+6+5x7? Points to whoever can answer! (:

Mathematics
2 answers:
spayn [35]3 years ago
4 0

Answer:

5x7= 35+6+4= 45

Step-by-step explanation:

babunello [35]3 years ago
3 0

Answer:

45

I have a $60 yearly membership with something

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How to calculate slope?
LUCKY_DIMON [66]

Answer:

Rise/run    rise over run

Step-by-step explanation:

y2-y1/x2-x1

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3 years ago
No link please……. Enter the value of b when the expression 30.4x + b is equivalent to 3.4 (6x-3.1)
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Answer:

61

Step-by-step explanation

sped

4 0
2 years ago
Read 2 more answers
Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
5 0
3 years ago
Read 2 more answers
La suma de dos números enteros consecutivos es<br> menor que 57.
g100num [7]

Answer: La respuesta es 28 y 29. Tengo que explicar?

7 0
3 years ago
Which expressions are equivalent to the one below. Check all that apply. 16^x
madam [21]

A.\ 4^x\cdot4^x=4^{x+x}=4^{2x}\qquad\text{used}\ a^n\cdot a^m=a^{n+m}\\\\B.\ 4^{2x}=(4^2)^x=16^x\qquad\text{used}\ (a^n)^m=a^{nm}\\\\C.\ 4^2\cdot4^x=4^{2+x}\\\\D.\ (4\cdot4)^x=16^x\\\\E.\ 4\cdot4^{2x}=4^{1+2x}\\\\F.\ 4\cdot4^x=4^{1+x}\\\\Answer:\ \boxed{B.\ and\ D.}

3 0
3 years ago
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