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dlinn [17]
3 years ago
5

5t + 5 = 30 solve for t

Mathematics
2 answers:
Stels [109]3 years ago
8 0
T=3 because 5x3+5=30
scoundrel [369]3 years ago
5 0
5t+5=30
divide both sides by 5
t+1=6
minus 1 both sides
t=5
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Point C ∈ AB , AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.
Shtirlitz [24]

let's say that C is "x" units farther from B, that means that CB = x, and therefore AC = 1.5x.


\bf \underset{\leftarrow ~~30~~\to}{\boxed{A}\stackrel{1.5x}{\rule[0.35em]{18em}{0.25pt}}C\stackrel{x}{\rule[0.35em]{10em}{0.25pt}}\boxed{B}}
\\\\\\
AB=AC+CB\implies \stackrel{AB}{30}=\stackrel{AC}{1.5x}+\stackrel{CB}{x}\implies 30=2.5x
\\\\\\
\cfrac{30}{2.5}=x\implies 12=x
\\\\[-0.35em]
~\dotfill\\\\
AC=1.5(12)\implies AC=18~\hspace{8em} CB=x\implies CB=12

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3 years ago
Y = 0.95X 7.95<br> Write and solve a linear equation to find how many songs he downloaded
Dmitry [639]
0.95 x 7.95 = 7.5525
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3 years ago
What are the 5 infinitives?
Ymorist [56]

The five types of infinitives are full infinitives, bare infinitives, split infinitives, continuous infinitives , and perfect continuous infinitive.

Explanation:

Types of infinitives:

Five types of infinitives are as follow:

  • Full infinitives : Add 'to' Infront of the verb to complete the the situation.
  • Bare infinitives: here " to" get omitted from the sentence.
  • Split infinitives : Here adjectives slides between infinitives marker.

To hear : full infinitives changes to split infinitives : to slowly hear.

  • Continuous infinitives: Action going for certain period of required time.

Example : to be missing

  • Perfect continuous infinitives: prior to a time :

Example : to have seen

Therefore, there are are five types of infinitives .

Learn more about infinitives here

brainly.com/question/1219442

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1 year ago
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5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Katena32 [7]

Answer:

(a)

5^{-3}=\frac{1}{125}

(b)

-5^{-3}=-\frac{1}{125}

(c)

(-5^{-3})^{-1}=-125

(d)

(-5^{-3})^{0}=1

Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

(-5^{-3})^{-1}=-125........Answer

(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

4 0
3 years ago
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