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Serggg [28]
3 years ago
11

30. The perimeter of a rectangle is 292 feet. The length of the rectangle is 4 feet less than 5 times the width. What is the len

gth and width of the rectangle?
a. length = 121, width = 25​​b. length = 114.3, width = 23.7
c. length = 25, width = 121​​d. length = 121.7, width = 24.3
Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0
Formula for perimeter ;
P = length + length + width + width 
P = 2l + 2w

l = -4 + 5w
l = 5w - 4

substitute into equation of perimeter 

292 = 2(5w - 4) + 2w

292 = 10w - 8 + 2w

292 + 8 = 10w + 2w 

300 = 12w

25 = w

substitute into eqution to find the length;

l = 5(25) - 4
l = 125 - 4
l = 121

therefore, the width is 25 and the length is 121

hope that helps, God bless!
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Step-by-step explanation:

Let <em>p</em> = proportion of business trip that were for  internal company visit.

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<em>p</em> = 0.19.

A sample of <em>n</em> = 950 business travelers are randomly selected.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

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The standard deviation of this sampling distribution of sample proportion is:

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*Use a <em>z</em>-table for the probability.

Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.

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                               = P (Z < 0.77) - P (Z < -3.08)

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*Use a <em>z</em>-table for the probability.

Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.

(c)

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Compute the value of P (0.14 < p' < 0.20) as follows:

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                               = P (Z < -0.77) - P (Z < -3.85)

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Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.

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