Answer:
for the first one its right 2 down 5
for the second one its right 5 down 2
for the third one its left 2 up 5
i hope this helps pls tell me if im wrong
bearing in mind that an explicit form is simply the sequence written as a function of some variables, so we simply simplify and add like-terms.

I just figured it out so I’ll answer it on this account lol.
Q1 = 32, Q2 = 45, Q3 = 52
Interquartile range = 52 - 32 = 20
Range = 68 - 21 = 47
<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
x=1/36
Step-by-step explanation:
