I just need the answer :)

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Answer:

3h12k2/2

Step-by-step explanation:

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Find the quotient and any excluded values. (x + 5/x^2 + 9x + 20)/(x^2-16/x-4)

Wittaler [7]

By (x + 5/x^2 + 9x + 20) you apparently meant the following:

x+5
----------------------
x^2 + 9x + 20

and by

(x^2-16/x-4)
x^2-16
you apparently meant ---------------
x - 4

Please use additional parentheses for clarity.

Dividing,

 x+5 (x-4)(x+4)
---------------------- * ---------------
x^2 + 9x + 20 x-4

Now, x^2 + 9x + 20 factors into (x+4)(x+5), so what we have now is

(x+5)(x+4)
------------------------- = 1 This is true for all x, so there are no exclusions.
(x+4)(x+5)

3 0

3 years ago

Please help 30 points will give brainliest

Vinil7 [7]

Answer:

thats correct

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The solution set of 2-3x/4-8=3x/4

deff fn [24]

Step-by-step explanation:

$\\ \tt{:}\leadsto \frac{2 - 3x}{4 - 8} = \frac{3x}{4} \\ \\ \tt{:}\leadsto 4(2 - 3x) = 3x(4 - 8) \\ \\ \tt{:}\leadsto 8 - 12x = 3x( - 4) \\ \\ \tt{:}\leadsto 8 - 2x = - 12x \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt{:}\leadsto 8 = - 12x + 2x \\ \\ \tt{:}\leadsto 8 = - 10x \\ \\ \tt{:}\leadsto x = \frac{ - 10}{8} \\ \\ \tt{:}\leadsto x = \frac{ - 5}{4}$