The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
Shesp ends reading 219 hours reading that book
55 - 3 = 52
52 - 3 = 49
49 - 3 = 46
46 - 3 = 43
43 is your answer
If this is all the information you have, it is not enough to conclude the region is square. we need more information
