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Drupady [299]
3 years ago
9

Least to greatest ordering integers

Mathematics
1 answer:
andriy [413]3 years ago
5 0

Answer:

5, 19, 24, 46, 77, 98

Step-by-step explanation:

Just write the numbers in order (I am assuming from least to greatest).  You can use a number line if necessary.



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Find the slope of the line passing through the points (-9, -6) and [<br> (-4, 5)
lora16 [44]

Answer:

y2-y1         5--6            11

--------   =.  --------   =     ----

x2-x1         -4 --9           5

Step-by-step explanation:

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3 years ago
Sophia's teacher is talking to the class about net worth. What does it mean for someone to have positive net worth?
tiny-mole [99]
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Assets is what you have (total money)
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A piece of wood is designed in the same of a cone.
77julia77 [94]

Answer:

See explanation

Step-by-step explanation:

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6 0
3 years ago
I need help with this problem and if you can help me I would definitely appreciate it :)
Georgia [21]

Answer:

a. x=2, y=13

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Step-by-step explanation:

3 0
3 years ago
A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation
Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an m\times n matrix.  Let T :U\to V  be the corresponding linear transformationover the field F and \theta be identity vector in V. Now if x\in Ker( T)\implies T(x)=\theta.

(1) The kernel of a linear transformation is a vector space : True.

Let x,y\in Ker( T), then,

T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)

hence the kernel is closed under addition.

Let \lambda\in F, x\in Ker( T), then

T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta

\lambda x\in Ker(T) and thus Ket(T) is closed under multiplication

Finally, fore all vectors u\in U,

T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta

\implies \theta\in Ker(T)

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is \mathbb R^m : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in \mathbb R^m

: False

The null space that is dimension of solution space of an m x n matrix is always in \mathbb R^n.

(4) The column space of A is the range of the mapping x\to Ax

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0
3 years ago
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