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ludmilkaskok [199]
3 years ago
12

What's three equivalent ratios to 12/14

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0
An equavalent ratio of 12\24 is 3\4
yulyashka [42]3 years ago
7 0
The first equivalent ratio is 3/4 since 12 is divisible by 4 and 3
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Ofelia has a certain amount of money. If she spends $12, then she has 1/5 of the original amount left. How much money did Ofelia
ZanzabumX [31]
X=amount of money Ofeila hasx-$12=(1/5)xLet's eliminate the fractions by multiplying both sides by 5...5(x-$12)=(5)(1/5)x5x-$60=xLet's subtract 5x from both sides...-5x+5x-$60=x-5x-$60=-4xLet's divide both sides by -4...(-$60)/(-4)=(-4x)/(-4)$15=x -< AnswerLet's check our work...x-$12=(1/5)x$15-$12=(1/5)($15)$3=$3
7 0
3 years ago
A number added to itself equals 3 less than the number..
ivanzaharov [21]
The answer would be -6.
3 0
3 years ago
What is the equation of a line that contains the point (2,1) and is perpendicular to the line: y = 3x – 4?
jeka57 [31]
Y = 3x - 4.....the slope here is 3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, u flip the slope and change the sign. So we will need a slope of -1/3...see how I flipped the slope of 3/1 and made it 1/3...and then changed the sign, making it -1/3.

y = mx + b
slope(m) = -1/3
(2,1)...x = 2 and y = 1
now we sub and find b, the y int
1 = -1/3(2) + b
1 = -2/3 + b
1 + 2/3 = b
3/3 + 2/3 = b
5/3 = b

so ur perpendicular equation is : y = -1/3x + 5/3
8 0
3 years ago
g Given the following premises: (1) a∧(b∨a) (2) ~c→~a (3) ~g→~a (4) g→e (5)~(d∨h) Prove the Conclusion: c∧~h?
KIM [24]

Answer:

See the argument below

Step-by-step explanation:

I will give the argument in symbolic form, using rules of inference.

First, let's conclude c.

(1)⇒a  by simplification of conjunction

a⇒¬(¬a) by double negation

¬(¬a)∧(2)⇒¬(¬c) by Modus tollens

¬(¬c)⇒c by double negation

Now, the premise (5) is equivalent to ¬d∧¬h which is one of De Morgan's laws. From simplification, we conclude ¬h. We also concluded c before, then by adjunction, we conclude c∧¬h.

An alternative approach to De Morgan's law is the following:

By contradiction proof, assume h is true.

h⇒d∨h by addition

(5)∧(d∨h)⇒¬(d∨h)∧(d∨h), a contradiction. Hence we conclude ¬h.    

8 0
3 years ago
PLEASE HELP ALMOST FINISHING ALBERA 1 PUT I NEED YOUR HELP PLEASE I BEG YOU BRAINLEST ANSWER!!!
tester [92]
59  is D 
because  with the point (-3,7) you substitute it into the equation, making it: 7=4x+b.  solve for b.  then you have y=4x+19.     work out the algebra in the possible choices and whatever equals y=4x+19 will be the answer. in this case, its D.


60 is C
same as above, you do the algebra of the equation. bring the one over after doing distribution with the 4 and voila!


61 is A
a relatively easy one, all you do is the the slope -4 where m goes, and 3 where b goes. y= -4x+3


62 is C.
this one requires more work.
chose one of the points, in this case (2,7) and put them into the equation. 
but wait, you need a slope! 
you get that use the formula (y2-y1)/(x2-x1) which will be
(7-5)/(2-3) which will be
-2.
now you have y-7= -2(x-2)
voila!



63 is  C.   y= 1/2x+3

64 is B. (3, -5)

66 is B. negative. the line  goes \ ( not / which is positive)

67 would be A. because it is positive and the I and the E are in the right places.


70 is C.  2/3.   as before, remember we can but the points into this equation and have (6-4)/(3-0) which = 2/3


71  is D.  y= 3x+10

72 is C. a third degree monomial

73 can't read


74 can't read 
 
75 can't read.

 
4 0
3 years ago
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