23400 x 8/100 = 1872 = the loss
1872 : 12 = 156= the loss each month
156/1872*100% = 8,33 % then round it
13 x 5 = 65
4 x 7 = 28
28 + 65 = 93
Your error is in you said 13 x 65 is 75
32m=36
m=36/32
m=9/8
that's the correct answer
Answer:
Between 38.42 and 49.1.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 43.76, standard deviation of 2.67.
Between what two values will approximately 95% of the amounts be?
By the Empirical Rule, within 2 standard deviations of the mean. So
43.76 - 2*2.67 = 38.42
43.76 + 2*2.67 = 49.1
Between 38.42 and 49.1.
The graph of the line y = -6 is a horizontal line which passes through the y axis at -6. On the other hand, the graph of the equation, x = 1/6 is a vertical line that passes through the x-axis at 1/6. The intersection of these lines is at a point that is expressed as (1/6, -6).
