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Rashid [163]
3 years ago
10

Hi, Make y the subject of the formula x = a-2byx^{2}

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

Step-by-step explanation:

x = a - 2byx²

x - a = -2byx²

-2byx^{2}= x- a\\\\       y = \frac{x-a}{-2bx^{2}}\\\\   y =\frac{-(x-a)}{2bx^{2}}\\\\y=\frac{ -x + a}{2bx^{2}}\\\\y=\frac{ a -x }{2bx^{2}}\\

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Jonas is planning out his route for an upcoming race. He uses negative numbers to represent points before
olya-2409 [2.1K]

Answer:

The finish line​

Step-by-step explanation:

Jonas is planning his trip using the finish line as reference point. He is using an interval scale (using meters as measurement) and the finish line = 0 meters or the starting point. Anything before the finish is negative and anything after is positive. In this case, his wife is located at 91 + 14 = 105 meters away from him. When you use an interval scale to measure distance, you must use absolute values to determine the distance because positive and negative points.  

6 0
3 years ago
Each year the school purchases agendas, this year the school sold 350 agendas at the cost of $1.137.50. If the school wants a pr
choli [55]
If they sell the same amount next year and want to reach $1,500, they must higher the price. to do that, they can divide the $1500 by the number of agendas. Do the math yourself, its not very hard.
8 0
3 years ago
box is filled with six yellow cards six red cards and three blue cards a card is chosen at random from the bag what is the proba
alexgriva [62]

Answer:

There is a 9/15 or 3/5

Step-by-step explanation:

There are a total of 15 cards, of those, 6 are red, so if you subtract 6 from 15, you get 9, which is the total amount of yellow and blue cards, which is what you were to not get a red card.

3 0
3 years ago
Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)
Triss [41]

g(r,\theta)=(r\cos\theta,r\sin\theta,\theta)\implies\begin{cases}g_r=(\cos\theta,\sin\theta,0)\\g_\theta=(-r\sin\theta,r\cos\theta,1)\end{cases}

The surface element is

\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

and the integral is

\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

=\displaystyle2\pi\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac\pi4(132\sqrt{17}-\sinh^{-1}4)

###

To compute the last integral, you can integrate by parts:

u=r\implies\mathrm du=\mathrm dr

\mathrm dv=r\sqrt{1+r^2}\,\mathrm dr\implies v=\dfrac13(1+r^2)^{3/2}

\displaystyle\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac r3(1+r^2)^{3/2}\bigg|_0^4-\frac13\int_0^4(1+r^2)^{3/2}\,\mathrm dr

For this integral, consider a substitution of

r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds

\displaystyle\int_0^4(1+r^2)^{3/2}\,\mathrm dr=\int_0^{\sinh^{-1}4}(1+\sinh^2s)^{3/2}\cosh s\,\mathrm ds

\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds

=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds

and the result above follows.

4 0
4 years ago
What is the simplest form of the expression (14.2a + 9.8b) – (13.1b – 0.2a) – (3.7a + 4.8b)?
makvit [3.9K]

The first; 10.7a-8.1b

5 0
3 years ago
Read 2 more answers
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