Answer:
true because her muscles are working and theres movement being done overall in the image.
Explanation:
The correct answer is the last statement.
If the regulatory serine is mutated to alanine, then acetyl-CoA carboxylase will get activated spontaneously and will produce malonyl-CoA. The increased concentrations of malonyl-CoA will obstruct the oxidation of fatty acids by preventing the entry of fatty acids into the mitochondria.
It is because the AMP-activated protein kinase phosphorylates the serine residues of acetyl-CoA carboxylase to inactivate it. If a mutation occurs in such residues, then the AMPL cannot phosphorylate acetyl-CoA carboxylase and this enzyme will get activated spontaneously.
In such a situation, there will be more than sufficient production of malonyl-CoA, which will inhibit the admittance of more fatty acid getting inside the mitochondria; this will indirectly prevent the oxidation of fatty acids.
Answer:
A) Deoxyribose- the purple pentagon
B) phosphate - the blue circle
C) nitrogenous base - the blue rectangles in the middle that are connected
Explanation:
Easy:
1. 2K + Br2 — KBr
2. 4Sb + 3O2 — SB4 O6
Medium:
1. 2Na+2H2O — 2NaOH+H2
2. 2KNO3 — 3KNO2+O2
Hard:
1. 4NH3+5O2 — 4NO+6H2O
2. C2H5OH+3O2 — 2CO2+3H2O
