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Masja [62]
3 years ago
5

Ray and Kelsey have summer internships at an engineering firm.

Mathematics
1 answer:
hoa [83]3 years ago
7 0
? There’s nothing but
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The amount recenue in dollars, y, that jason receives from selling x posters is given by the equation y=4x. the cost of producin
pashok25 [27]
For this case we have the following equations:
 revenue: y = 4x
 cost: y = 1 / 2x + 280
 We must match both equations:
 4x = 1 / 2x + 280
 From here, we clear the value of x:
 4x-1 / 2x = 280
 7 / 2x = 280
 x = (2/7) * (280)
 x = 80
 Answer:
 
jason needs to sell 80 posters so that the cost and revenue are equal
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The sum of a number and five times its reciprocal is 4.5. Write a quadratic equation for the number, and use the quadratic formu
g100num [7]

Answer:

x= -2 and (x+3)=0, x= -3

Step-by-step explanation:

"The sum of a number" well we do not know what the number is right, so let's call the number x. So we know we have x and we are adding it to something because it says sum. What are we adding it to? "5 times its reciprocal". A reciprocal of a number is equal to 1/the number. So the reciprocal of x is just 1/x. But we want 5 times this so multiply by 5. So now we have x + 5(1/x). Now we need to set it equal to something to be able to solve it. The problem says the sum of a number and 5 times its reciprocal is -6, so x + 5(1/x) = -6. Now just use order of operations to solve for x. First multiply: x + 5/x =-6. Then the next stperfect is harder because we want to get x by itself but we have x + 5/x. A trick you can do here is multiply the whole equation by x. This cancels out the fraction for us: x(x + 5/x) = -6(x) becomes x^2 +5 = -6x. Now we have a quadratic equation, to solve this you have to Factor or use the quadratic formula. I'll try factoring: first we need all of the terms on one side: x^2 +5x +6 =0. Now we need factors of 6 that add or subtract to 5. There are a couple of options here we could use 6 and -1 or 2 and 3. 6 and -1 would not work because both signs in the equation are plus which means we need our factors to both be positive, also if you tried 6 and -1 and then foiled out the factors to check it, it would not work. So 2 and 3 have to be the factors so the equations equals (x+2)(x+3)=0. Now we set each factor equal to zero and solve for x: (x+2)=0, x= -2 and (x+3)=0, x= -3. Those are the two numbers that would work! Hope this helps!!

5 0
3 years ago
Read 2 more answers
Round 7.16 to the nearest tenth
Wittaler [7]
In this problem, I would say 7.16 to the nearest 10th would be 7.20 because 16 is closer to 20 then 10.
8 0
3 years ago
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