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kaheart [24]
3 years ago
5

1st Coordinate Point: (1.4)

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
Yea thats the coordinate plane good job
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Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo
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Answer:

x^6+3x^3+3+\dfrac{1}{x^3}

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}

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Answer:

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Step-by-step explanation:

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8 0
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(I think this will be helpful for you. if you can see the picture, it has more detail in it.)

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