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3 years ago

14

Find x and y. Give reasons to justify your solutions.

1 answer:

Dimas [21]3 years ago

6 0

Answer:

y=14° x=15.6°

Step-by-step explanation:

In the picture.

I hope that it's a clear solution.

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A cyclist rides his bike at a rate of

docker41 [41]

15 miles per hour right so anyways that will be split by the number of minutes per hour so first there are 60 mins in an hour so its 15 divided by 60 which is 0.25 next how many miles will the cyclist travel in 15 minutes so that would mean taking the answer from the above and multiply it by 15 since you need 15 min which is 3.75 miles in 15 min hope i helped rate brainiest so i can reach next lvl! :)

8 0

2 years ago

What's the value of the expression below:

elena-14-01-66 [18.8K]

Answer:

The answer is 5 5/8.

The correct answer is not in the options

3 0

3 years ago

Read 2 more answers

180% is equivalent to what decimal value

SVETLANKA909090 [29]

Answer:

1.8

Step-by-step explanation:

4 0

2 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

(b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

I need help on number 8 and please show how you solved it :))

dmitriy555 [2]

Answer:

32.04% to 2 decimal places.

Step-by-step explanation:

As a fraction it is 17.3 / 54

To get the percentage we multiply by 100:

= (17.3/54) * 100

= 32.04%

8 0

2 years ago