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olga55 [171]
3 years ago
9

A process is normally distributed and in control, with known mean and variance, and the usual three-sigma limits are used on the

control chart, so that the probability of a single point plotting outside the control limits when the process is in control is 0.0027. Suppose that this chart is being used in phase I and the averages from a set of m samples or subgroups from this process are plotted on this chart. What is the probability that at least one of the averages will plot outside the control limits when m
Mathematics
1 answer:
Aleks [24]3 years ago
7 0

Answer:

Check the explanation

Step-by-step explanation:

Ans=

A: For m = 5: P(³≥1) = 1 – P(³=0) = 1 – 0.9973^5 = 0.0134

M = 10: 1 – 0.9973^10 = 0.0267

M = 20: 1 – 0.9973^20 = 0.0526

M = 30: 1 – 0.9973^30 = 0.0779

M = 50: 1 – 0.9973^50 = 0.126

18)

Ans=

Going by the question and the explanation above, we derived sample values of the mean as well as standard deviation in calculating our probability, since that is the necessary value in determining the probability of an out-of-bounds point being plotted. Furthermore, we would know that that value for the possibility would likely be a poor es²ma²on, cas²ng doubt on anycalcula²ons we made using those values

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a student walks 8 steps east 6 steps northeast 9 steps north west what is her displacement? include magnitude and direction
kati45 [8]

The displacement is 18.03 steps, and the direction is 47.25°

<h3>How to get the displacement?</h3>

We know that displacement is the difference between the final position and the initial position.

We assume the initial position (0, 0). Let's define the positive x-axis as the east and the positive y-axis as the north.

First, the student moves 8 steps east, so she is at:

(0 + 8, 0)

Then she moves 6 steps northeast, so the new position is:

(6*cos(45°) + 8,  6*cos(45°))

Finally, she moves 9 steps due north, so we have:

(6*cos(45°) + 8,  6*cos(45°) + 9)

Then the final position is:

(12.24, 13.24)

So the displacement is:

D = (12.24, 13.24) - (0, 0) =  (12.24, 13.24)

The magnitude of the displacement is:

|D| = \sqrt{12.24^2 + 13.24^2} = 18.03

So the magnitude is 18.03 steps.

And the direction is given by the arctangent of the quotient between the y-component and the x-component:

\theta = Arctg(13.24/12.24) = 47.25 \°

If you want to learn more about displacements:

brainly.com/question/4931057

#SPJ1

8 0
2 years ago
Find the distance between the two points.<br> (-6, -7) and (154, - 43)
Vitek1552 [10]

Answer:

(160, 36)

Step-by-step explanation:

Distance is always positive because, well, you aren't -50 meters away from your house or something. You are just 50 meters away from your house. And 160 is the distance between -6 and 154, because there is one minus and one plus, you add them, because that is how far they are apart, and then-43 and -7 were easy just subtract them.

8 0
2 years ago
What's two thirds of a straight line?
Komok [63]
Well if the straight line is equal to 1 then your answer is 2/3 but if the straight line is not equal to 1 you need to know what it is equal to or you could use the equation y = (2/3)x
"x" would be the length of the straight line and "y" would be two-thirds of it
6 0
3 years ago
4 cups equals how many ounces
DanielleElmas [232]
4 cups equals 33.307 oz

5 0
3 years ago
Read 2 more answers
Algebra:please answer #1 and show work
Novay_Z [31]
So 12 mins to 600 feet
35 mins=1900 feet
find the slope which is change in top over change in bottom (aka slope) so to find do
(y1-y2)/(x1-x2)
we want, per minute, so put the time as x1 and x2
x1=12
y1=600
x2=35
y2=1900
subsitutte
(600-1900)/(12-35)=-1300/-23=56.5 per minute
the answe ris 56.5 feet per minute or the last answer
4 0
3 years ago
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