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Andrews [41]
2 years ago
15

If you knew that the vertical intercept for a straight line was 15, that the slope was -.5, and that the independent variable ha

d a value of 8, the value of the dependent variable would be:
Mathematics
1 answer:
Finger [1]2 years ago
7 0
Y=-.5x+15 plug in 8 for x and you get 11
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How is the product of 2 and 5 shown on a number line?
Sedbober [7]

Answer:

d

Step-by-step explanation:

2 × -5 = -10

so number line should graduate from -5 to -10

5 0
2 years ago
Write the equation of the line given the two points. (1,-2) and (1,5)
Vinvika [58]

Answer:

x=1

Step-by-step explanation:

y=mx+b

5--2/1-1

7/0

6 0
2 years ago
graph 1 graph 2 graph 3 graph 4 Which graph represents the function f(x) = x2 + 3x + 2? A. graph 1 B. graph 2 C. graph 3 D. grap
stiv31 [10]

Answer:

See attachment

Step-by-step explanation:

To see clearly the graph that represents

f(x) =  {x}^{2}  + 3x + 2

we rewrite in vertex form to get;

f(x) = (x +  \frac{3}{2})^{2}  -  \frac{1}{4}

This is a vertical parabola with vertex at (-1.5,-0.25) and opens upwards.

The required graph is shown in the attachment.

3 0
2 years ago
PLEASE HELP 70 POINTS
AlexFokin [52]

Answer:

-1 = -5

0 = -1

2 =  5

Step-by-step explanation:

In order to do this you need to follow these five (5) steps:

1) Know what each of the variables mean in an equation of a line. The equation of a line is y = mx + b where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept. (Remember that the slope is the steepness  of a line and the y-intercept is the point where the line intersects  the y-axis. The x- and y-coordinates are values of the points on the line of y = 3x - 1.)

2) Identify the m (slope) and the b (y-intercept). The slope is 3, which can also be written as 3/1. The y-intercept is -1. (Remember that subtraction of 1 is the SAME thing as adding -1!) Since the y-intercept is a point it will be plotted at (0, -1).

3) Plot the y-intercept first. Start at the origin (intersection of the x- and y-axes) since the x coordinate is 0. Then move DOWN 1 unit since the y-coordinate is negative.

4) Use the m (slope) to plot at least three new points. The slope can also be represented as "rise/run" or the amount of units that you move UP or DOWN (vertically), then LEFT or RIGHT (horizontally). (Remember: if the numerator is positive (move UP); numerator is negative (move DOWN); denominator is POSITIVE (move RIGHT); denominator is NEGATIVE (move LEFT)). Since our slope is 3/1, and both the numerator and denominator are POSITIVE, that means we will be "rising" (moving UP) 3 units and "running" (moving RIGHT) 1 unit.

Start at the y-intercept  of (0, -1) and move up 3 units and to the right 1 unit. You should be at (1, 2). Plot a point here. Then do it again. You should now be at (2, 5). Plot another point. Now, do it one more time. You should now be at (3, 8). Plot your last point. (If you wish to continue plotting additional points, feel free to do so.)

4 0
3 years ago
Read 2 more answers
If f(x)=3x+1 then f(a+h)-f(a)
Varvara68 [4.7K]
F(x) = 3x+1
put x = a+h
f(a+h)  = 3(a+h) + 1
f(a+h) = 3a + 3h + 1
put x = a
f(a) = 3a + 1
f(a+h)-f(a) = 3a + 3h + 1 -(3a+1)
f(a+h)-f(a) = 3a +3h + 1 - 3a -1
f(a+h)-f(a) = 3h
7 0
2 years ago
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