Answer: at the equator the normal force will be 3.4N less and at the North Pole = 980N
Explanation:
So, we will start the Calculation by considering the equation below;
Fnet = F(g) - F(N); where Fnet = mv^2/ r.
Hence, F(g) - F(N) = mv^2/ r -------------(1).
Making F(N) the subject of the formula, we have;
F(N) = Gm1m2/r^2 - mv^2/r.
Thus, we have;
Gm1m2/r^2 = 6.68 × 10^-11 × (5.98 × 20^24) × 100/ 6.38 × 10^6 = 980N.
Also, we have;
mv^2/r = m4π^2r/T^2.
100 × 6.38 ×10^6 × 4π^2/(24 × 3600)^2 = 3.4N
Therefore, at the equator the normal force will be 3.4N less and at the North Pole = 980N.
<span>I'm not sure I
completely understand what the question is asking for. When I look at
the plates, it looks like they all fit together like a giant puzzle.
They separated due to tectonic plates shifting over hundreds of years.
This was based on the theory that there was a supercontinent (one giant
landmass). I'm not sure how much this helps, but I hope it does. Good
luck!!
</span>
Answer:
Scientists used major changes in life forms in the fossil record to form the geologic time scale.
Answer:
a. on the earth’s surface where the initial release of seismic energy occurs.
Explanation:
