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Bad White [126]
3 years ago
8

We are running late for school and we want to make our 0.5 kg tea (it’s at 90 C) colder. Let’s assume we can drink tea when it’s

50 C. We decided that it would be more convenient to drop an ice (0 C) since it will get cold soon. What mass of ice needs to be put in for this to happen?
Physics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

Answer:

x=0.154kg

Explanation:

(x*L)+(0.5kg*4200*50)+(x*4200*(-50)=0

(x*333 000J/kg*c)+(0.5kg*4200J/kg*C*(-40C))+(x*4200J/kg*C*50C)=0

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ra1l [238]

For this case, the first thing we must do is define a reference system.

Suppose that the positive direction of the reference system is upward.

We have that the sum of forces in the vertical axis is given by:

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3 years ago
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4 years ago
A 80 ohms resistor, 0.2 H inductance and 0.1 mF capacitor are connected in series across a generator (60 Hz, V rms=120 V). Deter
qaws [65]

Answer:

Impedance = 93.75 ohms

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Explanation:

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= \sqrt{8788.511} = 93.747 ohms  

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3 years ago
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v = 0.20 m/s

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