1. The change in momentum follows the formula:
Change in Momentum = mΔv,
where m is the mass and v is the velocity
Change in momentum = (700 kg)(15 m/s - 30 m/s) =<em> -10,500 kg·m/s</em>
2. For this problem, the formula for impulse, J, is
J = FΔt
Before answering part a, we answer for part b first.
Part B.
F = ma
where
a = Δv/t = (15 - 30)/5 = -1 m/s²
So,
F = (700 kg)(-1 m/s²) = <em>-700 N</em>
Part A.
J = (-700 N)(5 s) =<em> -3,500 N·s</em>
Answer: thanks for the point
Explanation:
Taking the vertical component of the displacement
1.1 - 0.2 = 0.9 mile
The horizontal component of the displacement
-0.3 mile
The magnitude of the displacement is
√[ (0.9)² + (-0.3) ] = 0.95 mile
The direction is
θ = tan-1 (-0.3/0.9)
θ = 161.57 degrees.
