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4 years ago

GEOMETRY HELP PLEASE It's question 7 only

Mathematics

2 answers:

Ray Of Light [21]4 years ago

5 0

X = 4 and x = -4 hope this helps

sweet-ann [11.9K]4 years ago

5 0

The possible lengths would be AD or BA

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Jeff sold the pumpkins he grew for $7 each at the farmers market. If Jeff sold 30 pumpkins how much money did he make. Write an

SVEN [57.7K]

Jeff made $210 by selling 30 pumpkins.

Step-by-step explanation:

Given,

Selling price of each Pumpkin = $7

Number of pumpkins sold by Jeff = 30

We will multiply number of pumpkins sold by selling price per pumpkin.

Amount made by Jeff = Price per pumpkin * Number of pumpkins

Amount made by Jeff = 7 * 30 = $210

Therefore;

Jeff made $210 by selling 30 pumpkins.

Keywords: multiplication

Learn more about multiplication at:

#LearnwithBrainly

8 0

3 years ago

Solve the initial-value problem y' = x^4 - \frac{1}{x}y, y(1) = 1.

natta225 [31]

The ODE is linear:

$y'=x^4-\dfrac yx$

$y'+\dfrac yx=x^4$

Multiplying both sides by $x$ gives

$xy'+y=x^5$

Notice that the left side can be condensed as the derivative of a product:

$(xy)'=x^5$

Integrating both sides with respect to $x$ yields

$xy=\dfrac{x^6}6+C$

$\implies y(x)=\dfrac{x^5}6+\dfrac Cx$

Since $y(1)=1$ ,

$1=\dfrac16+C\implies C=\dfrac56$

so that

$\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}$

4 0

3 years ago

When will a ratio equal a decimal between 0 and 1?

ira [324]

Answer:

Any-where below 1 and above 0

Step-by-step explanation:

I had this problem in math and my teacher told me this

8 0

3 years ago

Please help!! I need to get this! Brainliest For Right Anwser!

Doss [256]

Answer:

Data set A best fit by the regression line.

7 0

4 years ago

Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin

jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

GIVEN :-

There are 2 right-angled triangles.

In the triangle on the right side ,

Hypotenuse = 26m
Base = 10m

In the triangle on the left side ,

Base = 18m

TO FIND :-

Length of the common perpendicular to both triangles.
Length of the hypotenuse of the triangle on the left side.

FACTS TO KNOW BEFORE SOLVING :-

$Hypotenuse = \sqrt{Base^2 + Perpendicular^2}$ .
$Perpendicular = \sqrt{Hypotenuse^2 - Base^2}$

SOLUTION :-

In the triangle on the right side ,

$Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m$

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

$Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m$

∴ x = 30m

3 0

3 years ago