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ElenaW [278]
3 years ago
10

How to do this 4 question help asap pls​

Mathematics
2 answers:
fgiga [73]3 years ago
8 0

$$$$$$$$$&&&&&&&&&%%%%%%%%

<h2><u>Q10</u></h2>

<em>a) </em>2^(-1) = 1/2

a) 2^(-1) = 1/2<em>b) </em>2^(-3) = 1/2^3

a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3 = 1/8

a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3 = 1/8<em>c) </em>2^(-2) = 1/2^2

a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3 = 1/8c) 2^(-2) = 1/2^2 = 1/4

<h2>a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3 = 1/8c) 2^(-2) = 1/2^2 = 1/4<u>Q11</u></h2>

<em>a</em><em>)</em><em> </em>3^(-2) = 1/ 3^2

a) 3^(-2) = 1/ 3^2 = 1/ 9

a) 3^(-2) = 1/ 3^2 = 1/ 9<em>b</em><em>)</em><em> </em>2^(-3) = 1/ 2^3

a) 3^(-2) = 1/ 3^2 = 1/ 9b) 2^(-3) = 1/ 2^3 = 1/8

a) 3^(-2) = 1/ 3^2 = 1/ 9b) 2^(-3) = 1/ 2^3 = 1/8<em>c</em><em>)</em><em> </em>6^(-1) = 1/6

<h2>a) 3^(-2) = 1/ 3^2 = 1/ 9b) 2^(-3) = 1/ 2^3 = 1/8c) 6^(-1) = 1/6<u>Q12</u></h2>

<em>a)</em> 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4

a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4 =21/4

a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4 =21/4<em>b)</em> 10^(-1) + 10^0 + 10^3 = 1/10 + 1 +1000

a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4 =21/4b) 10^(-1) + 10^0 + 10^3 = 1/10 + 1 +1000 = 1001.1

<h2>a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4 =21/4b) 10^(-1) + 10^0 + 10^3 = 1/10 + 1 +1000 = 1001.1<u>Q13</u></h2>

<em>a)</em> 100 =10^2

a) 100 =10^2<em>b)</em> 1000 = 10^3

<h2>a) 100 =10^2b) 1000 = 10^3<u>Q14</u></h2>

<em>a) </em>9^2 x 9^3 = 9^(2+3)

a) 9^2 x 9^3 = 9^(2+3) = 9^5

a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049

a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049<em>b) </em>8 x 8^2 = 8^(1+3)

a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4

a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512

a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512c) 7^5 ÷ 7^2 = 7^(5-2)

a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512c) 7^5 ÷ 7^2 = 7^(5-2) = 7^3

a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512c) 7^5 ÷ 7^2 = 7^(5-2) = 7^3 = 343

&&&&&&&%%%%%%%%$$$$$$$&&&&&

Gnesinka [82]3 years ago
8 0

Answer:

Q10:

Apply the exponent rule that x^{-y} =\frac{1}{x^y}

a) 2^{-1} =\frac{1}{2^1} = 0.5

b) 4^{-1} =\frac{1}{4^1} = 0.25

c) 2^{-2}=\frac{1}{2^2} =\frac{1}{4} = 0.25

Q11:

a) 3^{-2} =\frac{1}{3^2} =\frac{1}{9}

b) 2^{-3} =\frac{1}{2^3} =\frac{1}{8}

c) 6^{-1} =\frac{1}{6^1}= \frac{1}{6}

Q12:

a) 2^2+2^0+2^{-2}=4+1+\frac{1}{4} =\frac{21}{4}

b) 10^{-1} +10^{0}+10^{-3}=\frac{1}{10}+1+1000=\frac{10011}{10}

Q13:

a) 100=10^{2}

b) 1000=10^{3}

c) 0.01=10^{-2}

Q14:

a) 9^{2}*9^{3}=9^{2+3}=9^{5}

b) 8*8^{2}=8^{1+2}=8^{3}

c) 7^{5} ÷ 7^{2}=7^{5-2}=7^{3}

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