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posledela
4 years ago
7

An elixir of ferrous sulfate contains 220 mg of ferrous sulfate in each 5 ml. if each milligram of ferrous sulfate contains the

equivalent of 0.2 mg of elemental iron, how many milligrams of elemental iron would be represented in each 5 ml of the elixir?
Chemistry
1 answer:
natita [175]4 years ago
7 0
To determine the mass of elemental iron in the elixir, we need to understand the given values given above. We are given the following:

Mass of ferrous sulfate = 220 mg
Volume of the elixir = 5 mL
Mass of elemental iron / mass of ferrous sulfate = 0.2 mg Fe / mg ferrous sulfate

Therefore, from the given values, we simply multiply the mass of the ferrous sulfate in the elixir and the equivalent mass of elemental iron per mass of ferrous sulfate. We do as follows:

Mass of Fe = 220 mg ferrous sulfate  ( 0.2 mg Fe / mg ferrous sulfate )
Mass of Fe = 44 mg
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3 years ago
Consider the KF molecule, which has an ionic bond. The bond length is 2.17 x 1010 m (a) Calculate the energy required to dissoci
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Answer:

a) +640 kJ/mol or +1.06x10⁻¹⁸ J

b) +276 kJ/mol

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To dissociate the molecule, the bond must be broken, thus, it's necessary energy equal to the energy of the bond, which can be calculated by:

E = (Q1*Q2)/(4*π*ε*r)

Where Q is the charge of the ions, ε is a constant (8.854x10⁻¹²C²J ⁻¹ m⁻¹), and r is the bond length. Each one of the ions has a charge equal to 1. The elementary charge is 1.602x10⁻¹⁹C, which will be the charge of them.

1 mol has 6.022x10²³ molecules (Avogadros' number), so the energy of 1 mol is the energy of 1 molecule multiplied by it:

E = 6.022x10²³ *(1.602x10⁻¹⁹)²/(4π*8.854x10⁻¹²*2.17x10⁻¹⁰)

E = +640113 J/mol

E = +640 kJ/mol

Or at 1 molecule: E =640/6.022x10²³ = +1.06x10⁻²¹ kJ = +1.06x10⁻¹⁸ J

b) The energy variation to dissociate the molecule at its neutral atoms is the energy of dissociation less the difference of the ionization energy of K and the electron affinity of F (EA):

498 = 640 - (418 - EA)

640 -418 + EA = 498

222 + EA = 498

EA = +276 kJ/mol

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