Answer:
61.9mL
Explanation:
Given parameters:
Initial volume = 49.7mL
Initial temperature = 20°C = 293K
Final temperature = 92°C = 365K
Unknown:
Final volume = ?
Solution:
To solve this problem, we simply apply the Charles's law which states that "the volume of a fixed mass of a gas varies directly as it absolute temperature if the pressure is constant";
V and T are volume and temperature values
1 and 2 are initial and final states
Now insert the parameters and solve;
= 
V2 = 61.9mL
Answer:
Homogénea
Explanation:
Una mezcla homogénea ocurre cuando se unen dos o más sustancias y no se pueden identificar después de ser unidas
En este caso no se logran identificar los compuestos
The answer is Human behavior.
1.1 / 2 = .7 --> 2.86 yrs
.7 / 2 = .45 —> 5.72 yrs
.45 / 2 = .225 —> 8.58 yrs
.225 / 2 = .1125 —> 11.44 yrs
So, for the sample of plutonium to reach .140 mg it should take a little less than 11.44 years.
Hope this helps
Answer : The final temperature of the metal block is, 
Explanation :
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of aluminum = 55 g
= mass of water = 0.48 g
= final temperature = ?
= temperature of aluminum =
= temperature of water =
= specific heat of aluminum = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![55g\times 0.900J/g^oC\times (T_{final}-25)^oC=-[0.48g\times 4.184J/g^oC\times (T_{final}-25)^oC]](https://tex.z-dn.net/?f=55g%5Ctimes%200.900J%2Fg%5EoC%5Ctimes%20%28T_%7Bfinal%7D-25%29%5EoC%3D-%5B0.48g%5Ctimes%204.184J%2Fg%5EoC%5Ctimes%20%28T_%7Bfinal%7D-25%29%5EoC%5D)
Thus, the final temperature of the metal block is,
