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4 years ago

Please help me solve this

Mathematics

1 answer:

Ugo [173]4 years ago

7 0

The slope of the line is 4/5!

I hope this helped! Mark me Brainliest! :) -Raven❤️

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What is the equation of a circle centered at the origin with radius 15?

sashaice [31]

Answer:

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( where r is the radius )

Here r = 15, thus

x² + y² = 15² , that is

x² + y² = 225 → D

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3 years ago

Divide polynomial by the monomial. Simplify answer completely.

forsale [732]

Answer:

Hi my lil bunny!

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$- ( 6x + 1 - \frac{2}{5x} )$ or it could be $- \frac{30x^2 + 5x -2}{5x}$

Step-by-step explanation: Factor the numerator and denominator and cancel the common factors. OR Move the negative in front of the fraction.

Try both of them because they both could be right.

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3 years ago

What can i do to inprove my math skills

myrzilka [38]

Answer:

Practice, study, get involved in school activities involving math, don’t get too stressed out when it doesn't work, and always try again.

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2 years ago

Read 2 more answers

Suppose the half-life of a certain radioactive substance is 12 days. Find the time when there will be 20% of the initial substan

vazorg [7]

Answer: 2.4% I think

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3 years ago

Write an equation that goes through (8,1) and is perpendicular to 2y + 4x =12

Serggg [28]

Answer:

2y -x + 6 = 0

Step-by-step explanation:

Here a equation and a point is given to us and we are interested in finding a equation which is perpendicular to the given equation and passes through the given point .

The given equation is ,

$\sf \longrightarrow 2y + 4x = 12 \\$

$\sf \longrightarrow 4x + 2y = 12$

Firstly convert this into slope intercept form , to find out the slope of the line.

$\sf \longrightarrow 2y = -4x +12\\$

$\sf \longrightarrow y =\dfrac{-4x+12}{2}\\$

$\sf \longrightarrow y =\dfrac{-4x}{2}+\dfrac{12}{2}\\$

$\sf \longrightarrow \red{ y = -2x + 6 }$

Now on comparing it to slope intercept form which is y = mx + c , we have ,

m = -2

And as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be negative reciprocal of the slope of the given line. Therefore ,

$\sf \longrightarrow m_{\perp}=\dfrac{-1}{-2}=\red{\dfrac{1}{2}}$