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4 years ago

What is the answer to this

Mathematics

2 answers:

amid [387]3 years ago

7 0

<h3>Answer: first choice, $\text{ABCD} \cong \text{A'B'C'D'}$ </h3>

Explanation:

Any rotation will keep the angles the same measure. The amount of rotation doesn't matter, and the center of rotation doesn't affect things either. So if angle A is something like 87 degrees, then angle A' is also 87 degrees. Therefore, angles A and A' pair up and correspond. The same can be said about the other pairs of angles.

So quadrilateral ABCD is congruent to quadrilateral A'B'C'D'. The order of the letters is important so that they align and match up properly.

AlladinOne [14]3 years ago

4 0

Answer:

ABCD ≅ A'B'C'D'

Step-by-step explanation:

When a figure is rotated, its orientation stays the same. This means that the pre-image and the image are labeled in the same direction. Therefore, ABCD ≅ A'B'C'D'

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two groups of students order cheeseburgers and chicken nuggets at mcdonald’s. one order of 9 cheeseburgers and 4 chicken nuggets

BlackZzzverrR [31]

Answer:

$1.19

Step-by-step explanation:

Let the cost of a cheeseburger be $b and that of a chicken nugget be $n.

From the given information, we can form 2 equations.

9b +4n= 22.37 -----(1)

3b +4n= 15.23 -----(2)

Notice that the 2 equations have '4n' in them. I'll be using elimination method to solve the equation by getting rid of the 4n.

(1) -(2):

9b +4n -(3b +4n)= 22.37 -15.23

9b +4n -3b -4n= 7.14

6b= 7.14 (simplify)

b= 7.14 ÷6 (÷6 on both sides)

b= 1.19

Thus, a cheeseburger cost $1.19.

8 0

4 years ago

Sam was asked to place the numbers shown below in order from least to greatest.

Aloiza [94]

Answer:

There's no question here or picture

Step-by-step explanation:

8 0

3 years ago

X²+y²-6x+14y-1=0 and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

3 years ago

Find all the solutions in there interval (0,2pi) for cos5x=-1/2

oee [108]

Answer:

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

$cos5x=-\frac{1}{2}$

Solving for 5x:

$5x=\frac{2\pi}{3}+2n\pi$

$5x=\frac{4\pi}{3}+2n\pi$

The values for x will be

$x=\frac{\frac{2\pi}{3}+2n\pi}{5}$

$x=\frac{\frac{4\pi}{3}+2n\pi}{5}$

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval $(0,2\pi)$

For n=0

$x=\frac{\frac{2\pi}{3}}{5}=\frac{2\pi}{15}$

$x=\frac{\frac{4\pi}{3}}{5}=\frac{4\pi}{15}$

For n=1

$x=\frac{\frac{2\pi}{3}+2\pi}{5}=\frac{8\pi}{15}$

$x=\frac{\frac{4\pi}{3}+2\pi}{5}=\frac{2\pi}{3}$

For n=2

$x=\frac{\frac{2\pi}{3}+4\pi}{5}=\frac{14\pi}{15}$

$x=\frac{\frac{4\pi}{3}+4\pi}{5}=\frac{16\pi}{15}$

For n=3

$x=\frac{\frac{2\pi}{3}+6\pi}{5}=\frac{4\pi}{3}$

$x=\frac{\frac{4\pi}{3}+6\pi}{5}=\frac{22\pi}{15}$

For n=4

$x=\frac{\frac{2\pi}{3}+8\pi}{5}=\frac{26\pi}{15}$

$x=\frac{\frac{4\pi}{3}+8\pi}{5}=\frac{28\pi}{15}$

For n=5 we would find values such as

$x=\frac{\frac{2\pi}{3}+10\pi}{5}=\frac{32\pi}{15}$

$x=\frac{\frac{4\pi}{3}+10\pi}{5}=\frac{34\pi}{15}$

which don't lie in the interval $(0,2\pi)$

The whole set of results is

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

6 0

4 years ago

(15 + 9) + 13 = 15+ (9 + 13)

egoroff_w [7]

Answer:

64  te quiero mucho ygrfrf7rttffrtx

3 0

3 years ago