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Rzqust [24]
3 years ago
10

What is the answer to this

Mathematics
2 answers:
amid [387]3 years ago
7 0
<h3>Answer: first choice, \text{ABCD} \cong \text{A'B'C'D'}</h3>

Explanation:

Any rotation will keep the angles the same measure. The amount of rotation doesn't matter, and the center of rotation doesn't affect things either. So if angle A is something like 87 degrees, then angle A' is also 87 degrees. Therefore, angles A and A' pair up and correspond. The same can be said about the other pairs of angles.

So quadrilateral ABCD is congruent to quadrilateral A'B'C'D'. The order of the letters is important so that they align and match up properly.

AlladinOne [14]3 years ago
4 0

Answer:

ABCD ≅ A'B'C'D'

Step-by-step explanation:

When a figure is rotated, its orientation stays the same. This means that the pre-image and the image are labeled in the same direction. Therefore, ABCD ≅ A'B'C'D'

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4. Identify the zeros and the graph of the function y = x(x − 2)(x + 5).
Natalka [10]

The zeros of

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

are

x=0,x=-2,x=-5x=0,x=−2,x=−5

EXPLANATION

The given function is

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

To find the zeros of the above function, we just have to equate the function to zero and solve for x.

x(x + 2)(x + 5) = 0x(x+2)(x+5)=0

This implies that,

x = 0 \: \: or \: x + 2 = 0 \:or \: x + 5 = 0x=0orx+2=0orx+5=0

x = 0 \: \: or \: x = - 2\:or \: x = - 5x=0orx=−2orx=−5

To graph the above function, we need to consider the multiplicity.

We can see that the multiplicity of the roots are odd. This means that, the graph crosses the x-axis at each x-intercept.

We also need to consider the position of the graph on the following intervals,

x < - 5x<−5

When

x = - 10x=−10

y = - 10( - 8)( - 5) \: < \: 0y=−10(−8)(−5)<0

The graph is below the x-axis.

- 5 \: < \: x \: < \: - 2−5<x<−2

When

x = - 3x=−3

y = - 3(2)( - 1) \: > 0y=−3(2)(−1)>0

The graph is above the x-axis.

- 2 \: < \: x < \: 0−2<x<0

when

x = - 1x=−1

y = -1(1)(4) \: < \: 0y=−1(1)(4)<0

The graph is below the x-axis.

Finally the interval,

x \: > \: 0x>0

when

x = 1x=1

y = 1(3)(6) \: > \: 0y=1(3)(6)>0

The graph is above the x-axis.

We can now use the above information to sketch graph as shown in the diagram above

3 0
2 years ago
Whwat is 2 pwus 1 pweass hellpe itz vary hard
hichkok12 [17]

Answer: 3

Step-by-step explanation: 2+1=3

8 0
3 years ago
Read 2 more answers
Consider the following equations. f(x) = − 4/ x3, y = 0, x = −2, x = −1. Sketch the region bounded by the graphs of the equation
Sindrei [870]

Answer:

1.5 unit^2

Step-by-step explanation:

Solution:-

- A graphing utility was used to plot the following equations:

                         f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2

- The plot is given in the document attached.

- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).

- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.

We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).

The double integration formulation can be written as:

                           A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2

Answer: 1.5 unit^2 is the amount of area bounded by the given curve f ( x ) and the boundary equations.

Download docx
3 0
2 years ago
⚠️⚠️please answer⚠️⚠️
Maurinko [17]

Answer:

The slope is -3/4 and the y-intercept is 1.

Step-by-step explanation:

B is the point where the line cross the y-axis, or vertical axis. Slope is the steepness of the line. Determined by rise over run. When the slope goes down 3 units, the slope goes to the right 4 units.

6 0
2 years ago
Read 2 more answers
each year a tree grows 26 cm. after 4.5 years the tree is 292 cm. how tall was the tree when he moved into the house
jeka57 [31]
26×4=104
292-104=188
26÷2=13
188-13=175cm

the tree was 175cm when he moved in
7 0
3 years ago
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