
radius r = 10 m
volume V = 4188.7902 m3
surface area A = 1256.63706 m2
circumference C = 62.8318531 m
In Terms of Pi π
volume V = 1333.33333 π m3
surface area A = 400 π m2
circumference C = 20 π m
40% of 44000 would be 17600
Since there is a common difference of one, this is an arithmetic sequence of the form a(n)=a+d(n-1) which in this case is:
a(n)=15+1(n-1)
All arithmetic sequences have a sum which is equal to the average of the first and last terms time the number of terms, mathematically:
s(n)=(2an+dn^2-dn)/2 (that is just the result of ((a+a+d(n-1))(n/2)) )
Since a=15 and d=1 this becomes:
s(n)=(30n+n^2-n)/2
s(n)=(n^2+29n)/2 so
s(10)=(100+290)/2
s(10)=195 logs
2 because the difference in the equation must equal 0 so it must equal 6 so 6/3 is 2. Therefore the answer is 2