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olchik [2.2K]
3 years ago
8

Andy runs at a constant speed of 548.7 feet in 7.6 seconds. How far does he run in one second. Round your answer to the nearest

tenth of a second. Fill in the blank. Andy ran _____ feet in one second. *
Mathematics
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

72.2 feet

Step-by-step explanation:

548.7 ÷ 7.6= 72.2

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olga_2 [115]
The answer is 4. you distribute the negative to make a positive sign and then add
4 0
3 years ago
PLEASE HELP
Natalka [10]

Answer:

7

Step-by-step explanation:

the median is the number in the middle of a sorted array

here it has 10 numbers, so the median will be the average of the 5th and the 6th number

the 5th number is 7 and the 6th number is 7

the average is (7+7)/2 = 7

so the median is 7

4 0
2 years ago
How do you rewrite the equation in the form 52m = 460
max2010maxim [7]
The answer is 115/13
8 0
3 years ago
Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t
Svet_ta [14]

Answer:

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}

[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}

[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]

Finally, the third vector of basis E is e3(t)=t^{2}

T[e3(t)]=T(t^{2})

in the equation : a2 = 1

T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}

Then

[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]

And that is the third column of [T]EE

Let's write our matrix

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

X=\left[\begin{array}{c}1&0&0\\\end{array}\right]

AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

8 0
3 years ago
Which equation represents a circle with a center at (–4, 9) and a diameter of 10 units?
ale4655 [162]

Answer:

(x + 4)^2 + (y – 9)^2 = 25

Step-by-step explanation:

The standard form for a circle is

(x - h)^{2} + (y - k)^{2}  = r^{2}     where (h, k) is the center and r is the radius

In your case, h = -4 and k = 9 and r = 5

So, (x + 4)^2 + (y – 9)^2 = 25

7 0
3 years ago
Read 2 more answers
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