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Alekssandra [29.7K]
4 years ago
13

Draw a regular pentagon so that it has a perimeter of 20 cm. Use the Regular Polygon Area Conjecture and a centimeter tyler to f

ind its approximate area.

Mathematics
1 answer:
Ratling [72]4 years ago
3 0

Answer:

Check the graph below. Area = 27.52 cm^{2}

Step-by-step explanation:

A Regular Pentagon has an interior angle of 108º an an exterior angle of 72º.

Since the perimeter is 20 cm, let's draw it respecting it those properties, besides all of the three sides must have the same measure.

And since we can divide it, into three triangles, we can calculate the area using tangent.

So, let's find out the area:

A_5=\frac{s^{2}n}{4tan(\frac{180}{n})} =\frac{4^{2}*5}{4tan\frac{180}{5}}\\ \\A\approx27.52cm^{2}

So check it down

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7 0
3 years ago
If O N = 8 x − 8 , L M = 7 x + 4 , N M = x − 5 , and O L = 3 y − 6 , find the values of x and y for which LMNO must be a paralle
posledela

Answer:

x=12\\y=\frac{13}{3}


Step-by-step explanation:

For it to be a parallelogram, opposite sides have to be of same length.

  • OL = NM, and
  • ON = LM

Using the expressions given, we can make 2 equations:

<u>Equation 1:</u>

OL=NM\\3y-6=x-5\\-x+3y=1


<u>Equation 2:</u>

ON=LM\\8x-8=7x+4\\


<em>Solving equation 2, we have x:</em>

8x-8=7x+4\\8x-7x=4+8\\x=12

<em>Plugging this value of x into equation 1, we can solve for y:</em>

-x+3y=1\\-(12)+3y=1\\-12+3y=1\\3y=13\\y=\frac{13}{3}

So,

x=12\\y=\frac{13}{3}



7 0
3 years ago
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