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ANTONII [103]
4 years ago
14

The ancient Greeks could bisect an angle using only a compass and straightedge.A. TrueB. False

Mathematics
2 answers:
Gala2k [10]4 years ago
5 0

Answer: True.

The ancient Greeks could bisect an angle using only a compass and straightedge.

Step-by-step explanation:

The ancient Greek mathematician <em>Euclid</em> who is known as inventor of geometry.

The Greeks could not do arithmetic. They had only whole numbers. They do not have zero and negative numbers.

Thus, Euclid and the another Greeks had the problem of finding the position of an angle bisector.

This lead to the constructions using compass and straightedge. Therefore, the straightedge has no markings. It is definitely not a graduated-rule.

As a substitute for using arithmetic, Euclid and the Greeks learnt to solve the problems graphically by drawing shapes .

xxMikexx [17]4 years ago
3 0

Answer: false

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1. Solve the given equation on the domain [0,2pi]
Mekhanik [1.2K]

Answer:

1.x = pi/3 or 4pi/3

2. x = -pi/6 +2pi*n  or 5pi/6 + 2pi *n  where n is an integer

Step-by-step explanation:

1. sqrt(3) tan x = 3

Divide each side by sqrt(3)

sqrt(3)/sqrt(3) tan x = 3/sqrt(3)

tan x = sqrt(3) * sqrt(3)/sqrt(3)

tan x = sqrt(3)

Take the inverse of each side

arctan (tanx) = arctan (sqrt(3))

x = arctan (sqrt(3))

x =pi/3  or - 2pi/3

Since the domain is between 0 and 2pi, add 2pi to - 2pi/3  since the trig functions  are circular

x = pi/3  or -2pi/3 + 6pi/3

x = pi/3 or 4pi/3


2.  3 tan x = -sqrt(3)

Divide each side by 3

3/3 tan x = -sqrt(3)/3

tan x = -sqrt(3)/3

Take the arctan of each side

arctan (tan x) = arctan ( -sqrt(3)/3)

x = arctan ( -sqrt(3)/3)

x =-pi/6 or 5pi/6

We want all values for x so add 2pi*n to each value where n is an integer

x = -pi/6 +2pi*n  or 5pi/6 + 2pi *n  where n is an integer

6 0
3 years ago
Can someone explain this to me &amp; also give me the answer for it
Vikentia [17]
Hey there!

You can write out equations for both of these situations. 

The first situation can be represented by f(x) = 382 + 2x, where 382 is the initial cost, x is the total amount of miles, 2x is the cost per additional mile, and f(x) equals to total that Jason has had to pay to drive his truck. 

The second situation can be presented by g(x) = 379 + 5x, where 379 is the initial amount Jason will get paid, x is the amount of miles he's driven, 5x is the money he's being paid depending on how many miles he's driven, and g(x) is the total amount he's been paid. 

You can graph these two equations on the computer or by hand to find where they will meet up. The place where they intersect will be the place where Jason breaks even. You can see on the graph I attached that, after one mile, the lines intersect and Jason spends and makes a total of 384 dollars. 

Hope this helped you out! :-)

4 0
3 years ago
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At Jefferson Middle School, eighty-two students were asked which sports they plan to participate in for the coming year. Twenty
blondinia [14]

Answer:

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8 0
3 years ago
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Svet_ta [14]
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df/dx=9x^(-2)  or if you prefer...

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4 years ago
13. A counterexample
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Answer:

b

Step-by-step explanation:

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3 years ago
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