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ANTONII [103]
4 years ago
14

The ancient Greeks could bisect an angle using only a compass and straightedge.A. TrueB. False

Mathematics
2 answers:
Gala2k [10]4 years ago
5 0

Answer: True.

The ancient Greeks could bisect an angle using only a compass and straightedge.

Step-by-step explanation:

The ancient Greek mathematician <em>Euclid</em> who is known as inventor of geometry.

The Greeks could not do arithmetic. They had only whole numbers. They do not have zero and negative numbers.

Thus, Euclid and the another Greeks had the problem of finding the position of an angle bisector.

This lead to the constructions using compass and straightedge. Therefore, the straightedge has no markings. It is definitely not a graduated-rule.

As a substitute for using arithmetic, Euclid and the Greeks learnt to solve the problems graphically by drawing shapes .

xxMikexx [17]4 years ago
3 0

Answer: false

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Factor completely.
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Answer:

B

Step-by-step explanation:

Given

y² - 12y + 32

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Answer:

<em>70%</em>

<em></em>

Step-by-step explanation:

Given

Number of Siblings:   ||    0  ||    1    ||      2     ||       3

Number of Students: ||    4  ||    18    ||    10     ||       8

Required

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First, we have to determine the total number of 10th grade students

Total = 4 + 18 + 10 + 8

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The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)

Solving for P(1)

P(1) = number of students with 1 sibling / total number of students

From the given parameters, we have that:

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P(1) = \frac{18}{40}

Solving for P(2)

P(2) = number of students with 2 siblings / total number of students

From the given parameters, we have that:

Number of students with 2 siblings = 10

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P(1) + P(2) = \frac{18}{40} + \frac{10}{40}

Take LCM

P(1) + P(2) = \frac{18 + 10}{40}

P(1) + P(2) = \frac{28}{40}

Divide numerator and denominator by 4

P(1) + P(2) = \frac{7}{10}

P(1) + P(2) = 0.7

Convert to percentage

P(1) + P(2) = 70\%

<em>Hence, the required probability is 70%</em>

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