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scoray [572]
2 years ago
12

Whats it called when 1 angle = 180 degrees

Mathematics
2 answers:
4vir4ik [10]2 years ago
3 0

Answer:

It's called a straight angle, it's a straight line.

Step-by-step explanation:

Literally a straight line.

Lunna [17]2 years ago
3 0

Answer:

Straight angle ..

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Determine whether each graph represents a linear or nonlinear function. Use the
ANTONII [103]

Answer:

  • x-intercepts: -3, -2, -1, 1, 2
  • y-intercept: 12
  • symmetry: none

Step-by-step explanation:

The x- and y-intercepts are the points where the graph crosses the x- and y-axes, respectively. If an odd-degree polynomial function has any symmetry, it will be symmetrical about the origin.

<h3>X-intercepts</h3>

The graph shows crossings of the x-axis at -3, -2, -1, 1, and 2. These are the x-intercepts. Expressed as coordinate pairs, each will have a y-coordinate of zero:

  (-3, 0), (-2, 0), (-1, 0), (1, 0), (2, 0)

<h3>Y-intercepts</h3>

If the function is not vertically scaled, the y-intercept of an odd-degree function will be the opposite of the product of the x-intercepts:

  -(-3)(-2)(-1)(1)(2) = 12

It will have an x-coordinate of zero:

  (0, 12) . . . y-intercept

A function can have at most 1 y-intercept.

<h3>Symmetry</h3>

There are two features of this graph that tell you it is an odd-degree function:

  1. the end behavior is in opposite directions
  2. there are an odd number of x-intercepts (x-axis crossings)

An odd-degree function will only be symmetrical about the origin. This function has more negative x-intercepts than positive ones, so is not symmetrical about the origin.

The graph has no symmetry.

__

<em>Additional comment</em>

Turning points without an x-axis-crossing on either side, or axis "touches" (not crossing) signify complex or even-multiplicity roots. The function will only be of odd degree if there are an odd number of x-axis crossings.

The end behavior of an odd-degree function will be in opposite directions: the infinity will match the sign of x if the leading coefficient is positive, or be opposite to the sign of x if the leading coefficient is negative.

7 0
1 year ago
I need help on this question as well.
Y_Kistochka [10]

8 is the answer, because 4 x 8 = 32

7 0
3 years ago
Read 2 more answers
Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or
NARA [144]

Answer:

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

Step-by-step explanation:

The function is:

f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y

The partial derivatives of the function are included below:

\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y

\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)

\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x

\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)

Local minima, local maxima and saddle points are determined by equalizing  both partial derivatives to zero.

y \cdot (8\cdot y -16\cdot x + 9) = 0

x \cdot (16\cdot y - 8\cdot x + 9) = 0

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

x\cdot (-8\cdot x + 9) = 0

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

y\cdot (8\cdot y+9) = 0

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}

The second derivatives of the function are:

\frac{\partial^{2} f}{\partial x^{2}} = 0

\frac{\partial^{2} f}{\partial y^{2}} = 0

\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9

Then, the expression is simplified to this and each point is tested:

H = -16\cdot y +16\cdot x -9

S1: (0,0)

H = -9 (Saddle Point)

S2: (3/8,-3/8)

H = 3 (Local maximum or minimum)

S3: (9/8, 0)

H = 9 (Local maximum or minimum)

S4: (0, - 9/8)

H = 9 (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64} (Local minimum)

S3: (9/8, 0)

f(\frac{9}{8},0) = 0 (Local maximum)

S4: (0, - 9/8)

f(0,-\frac{9}{8} ) = 0 (Local maximum)

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

4 0
3 years ago
Set 1: 21, 24, 36, 38, 40, 42, 44, 63, 85
Aleksandr-060686 [28]

Answer:

set 1 : 23.5

set 2 : 54

Step-by-step explanation:

lower quartile - upper quartile = answer

8 0
3 years ago
Read 2 more answers
Help me out plz................................
12345 [234]
I think it is A but make sure with someone else
7 0
2 years ago
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