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2 years ago

What is a good source to train numerical reasoning?

1 answer:

6 0

Numerical reasoning tests are often done to assess a person's ability to solve or interpret numerical data. A good source to train numerical reasoning is the use of computer education software's that deals with numerical data, the use of textbooks, self test etc.

<h3>What is done in Numerical reasoning tests?</h3>

Here, an individual is often required to analyze numerical data and then they are expected to draw conclusions from the data, which is often presented in tabular or graphical forms.

A person can improve their numerical reasoning by;

Constant Practice

Do make a study schedule and keep to it.
Do Practice as if you are going for a competition, etc.

A way that a person can improve their speed in an numerical test is to reduce the time it takes a person to take in the information that is shown in the numerical reasoning questions.

Learn more about numerical reasoning from

brainly.com/question/251701

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2 cubed x what x 5 = 120 <br><br>please i really need help

marin [14]

Answer:

2x3x5=120

Step-by-step explanation:

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1 year ago

Read 2 more answers

Please help, The first one to answers gets 10 points

babymother [125]

Answer:

6.75-2.33-1.75=2.67 hours

Step-by-step explanation:

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3 years ago

Evaluate.<br><br> (1/4)^-2 - (5^0x2) x 1^-1

blondinia [14]

Answer:

Step-by-step explanation:

Arithmetic expressions are best evaluated using a reliable calculator. The Google calculator always follows the Order of Operations, so can give you a good answer to such questions.

(1/4)^-2 - (5^0)(2)(1^-1)

= 16 - (1)(2)(1) . . . . evaluate the exponents first

= 16 -2 . . . . . . . . . evaluate the product next

= 14 . . . . . . . . . . . finally, evaluate the sum

___

The rule of exponents is ...

a^-b = 1/(a^b)

4 0

3 years ago

In Sweden, 10 people are struck by lightning every year, on average. Answer thefollowing questions about a given year in Sweden

emmainna [20.7K]

Answer:

a) 19.85% probability that a total of two people are struck by lightning during first four months of the year.

b) 22.68% probability that the year has 5 good and 7 bad months

Step-by-step explanation:

We are going to use the Poisson distribution and the binomial distribition to solve this question.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a.Find the probability that a total of two people are struck by lightning during first four months of the year.

10 people during a year(12 months).

In 4 months, the mean is $\mu = \frac{10*4}{12} = 3.33$

This is P(X = 2).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-3.33}*(3.33)^{2}}{(2)!} = 0.1985$

19.85% probability that a total of two people are struck by lightning during first four months of the year.

b.Say that a month is good is no one is struck by lightning, and bad otherwise. Find the probability that the year has 5 good and 7 bad months.

Probability that a month is good.

P(X = 0), Poisson

The mean is $\mu = \frac{10*1}{12} = 0.8333$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.8333}*(0.8333)^{0}}{(0)!} = 0.4346$

Find the probability that the year has 5 good and 7 bad months.

Now we use the binomial distribution, we want P(X = 5) when n = 12, p = 0.4346. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{12,5}.(0.4346)^{5}.(0.5654)^{7} = 0.2268$

22.68% probability that the year has 5 good and 7 bad months

3 0

3 years ago

What are the slopes of line A and line B? Look at the picture

Aloiza [94]

we can mark points on the graph shown , check the image I have shared with this for the points .

Formula for slope = $\frac{Y2-Y1}{X2-X1}$

So for Line A points are (1,3) and (0,-1)

So using t he formula slope is = $\frac{-1-3}{0-1}$

slope of line A =4

For Line B the points are (0,4) and (3,-5)

So using t he formula slope is = $\frac{-5-4}{3-0}$

slope of line B = -3

7 0

3 years ago