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Bogdan [553]
3 years ago
5

GUYS PLEASE HELP ME PLEASE HELP PLEASE PLEASE!!!!

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

18 , 18.901036

Step-by-step explanation:

3.052 * 6.193

estimate : 3 * 6 = 18

actual answer : 3.052 * 6.193 = 18.901036

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Find the slope of the line passing through the points (2,-9) and )1,-3)
nignag [31]

Hi there!

\large\boxed{\text{slope =} 6}

We can calculate slope using the following formula:

slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Plug in the corresponding points:

slope = \frac{-9-(-3)}{2-1}

Simplify:

slope = \frac{-6}{1} = -6

3 0
3 years ago
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schepotkina [342]

Answer:

Answer is in the attachment

6 0
3 years ago
if the corresponding sides of 2 quadrilaterals are propotional, then the 2 quadrilaterals must be similar
den301095 [7]

Answer:

False

Step-by-step explanation:

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5 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
NCERT SOLUTIONS FOR CLASS 7 <br><br>MATHS <br><br>ALL CHAPTERS<br>​
Galina-37 [17]

Answer:

https://www.learncbse.in/ncert-solutions-for-class-7-maths/

5 0
3 years ago
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